天真的我最开始以为可以写成list.distinct(x=>x.name);以为这样就可以按照name去重了，结果是不行的。这里记录下正确的用法。
1.这里是针对int集合 可以满足
#region 对数字集合的去重
//List<int> list = new List<int> { 1,1,2,3,4,5,5,6,6,7,7,7 };
//foreach (var item in list)
//{
// Console.Write(item+" ");
//}
//var res = list.Distinct();
//Console.WriteLine();
//Console.WriteLine("********************************");
//foreach (var item in res)
//{
// Console.Write(item+" ");
//}
//可以看到 对于数字来说 distinct可以实现去重
#endregion
2.对对象集合使用 失败
#region 对非数字类型去重失败的方法
//List<Student> list = new List<Student>
//{
// new Student{name="张三",age=20},
// new Student{name="张三",age=20},
// new Student{name="李四",age=20},
// new Student{name="李四",age=20},
// new Student{name="王五",age=20},
// new Student{name="赵六",age=20},
// new Student{name="陈启",age=20},
// new Student{name="陈启",age=20},
//};
//foreach (var item in list)
//{
// Console.Write(item.name + " ");
//}
//var res = list.Distinct();
//Console.WriteLine();
//Console.WriteLine("********************************");
//foreach (var item in res)
//{
// Console.Write(item.name + " ");
//}
//运行这段代码 可以看到去重失败了 下面来看正确的做法
#endregion
3.这才是正确的方法
class Program
{
static void Main(string[] args)
{
#region 对非数字类型去重正确
List<Student> list2 = new List<Student>
{
new Student{name="张三",age=20},
new Student{name="张三",age=20},
new Student{name="李四",age=20},
new Student{name="李四",age=20},
new Student{name="王五",age=20},
new Student{name="赵六",age=20},
new Student{name="陈启",age=20},
new Student{name="陈启",age=20},
};
foreach (var item in list2)
{
Console.Write(item.name + " ");
}
var res2 = list2.Distinct(new userCompare());
Console.WriteLine();
Console.WriteLine("********************************");
foreach (var item in res2)
{
Console.Write(item.name + " ");
}
//声明一个类 实现IEqualityComparer接口
//实现方法bool Equals(T x, T y);
//int GetHashCode(T obj);
//然后再内部写上比较的字段和属性 比较才能成功 才能去重
#endregion
Console.ReadLine();
}
}
public class Student
{
public int age { get; set; }
public string name { get; set; }
}
public class userCompare : IEqualityComparer<Student>
{
#region IEqualityComparer<user> Members
public bool Equals(Student x, Student y)
{
return x.name.Equals(y.name);
}
public int GetHashCode(Student obj)
{
return obj.name.GetHashCode();
}
#endregion
}
原文地址：https://www.cnblogs.com/yagamilight/p/12305538.html