题目:https://vjudge.net/contest/364745#problem/B
先用三分求出最高点Y,然后在进行二分,求出角度
注意写法 PI的弧度是
acos(-1)/2-EPS接近90度的时候相当于除以0二分的精度可以用迭代次数来保证,比如100次
#include <iostream> #include <cmath> using namespace std; const double EPS = 1e-8; int T; double x, y, v; double f(double a)//角度为a时对应的高度 { double t = x/(v*cos(a)); return v*sin(a)*t - 9.8/2*t*t; } int main() { cin >> T; while(T--) { cin >> x >> y >> v; double L = 0, R = acos(-1)/2-EPS; if(x==0) //特判,否则三角函数会智障掉 { if(v*v/2/9.8 > y) printf("%.6lf\n", R); else printf("-1\n"); continue; } for(int i=1;i<=100;i++) { double mid_L = (L+R) / 2; double mid_R = (mid_L+R) / 2; if(f(mid_L) > f(mid_R)) { R = mid_R; } else { L = mid_L; } } if(f(L) < y) {printf("-1\n"); continue;} R = L, L = 0; for(int i=1;i<=100;i++) { double mid = (L+R)/2; if(f(mid) < y) { L = mid; } else { R = mid; } } printf("%.6lf\n", L); } }
原文地址:https://www.cnblogs.com/SunChuangYu/p/12670631.html
时间: 2024-11-06 10:02:20