hdoj:2080

夹角有多大II

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 10656    Accepted Submission(s): 5510

Problem Description

这次xhd面临的问题是这样的:在一个平面内有两个点,求两个点分别和原点的连线的夹角的大小。

注:夹角的范围[0,180],两个点不会在圆心出现。

Input

输入数据的第一行是一个数据T,表示有T组数据。
每组数据有四个实数x1,y1,x2,y2分别表示两个点的坐标,这些实数的范围是[-10000,10000]。

Output

对于每组输入数据,输出夹角的大小精确到小数点后两位。

Sample Input

2
1 1 2 2
1 1 1 0

Sample Output

0.00
45.00
#include <iostream>
#include <string>
#include <cstdlib>
#include <stdio.h>
#include <cmath>
#define PI 3.141592653
using namespace std;

int main()
{
    int T;
    double x1, y1, x2, y2;
    double a,b,cosx, arcosx;
    cin >> T;
    while (T--)
    {
        cin >> x1 >> y1 >> x2 >> y2;
        a = x1*x2 + y1*y2;
        b = sqrt((x1*x1 + y1*y1)*(x2*x2 + y2*y2));
        cosx = a / b;
        arcosx = acos(cosx) /PI *180;
        printf("%.2lf\n", arcosx);
    }
    return 0;
}
时间: 2024-10-22 06:41:01

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