LeetCode——Spiral Matrix II

Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.

For example,

Given n = 3,

You should return the following matrix:

[
 [ 1, 2, 3 ],
 [ 8, 9, 4 ],
 [ 7, 6, 5 ]
]

原题链接:https://oj.leetcode.com/problems/spiral-matrix-ii/

之前的一题是将螺旋结构的二维数组转成一维数组,此题正好相反,故只需将原来的位置上取下来的元素放回去。

public class SpiralMatrixII {
	public static void main(String[] args) {
		int[][] matrix = new SpiralMatrixII().generateMatrix(3);
		for(int[] r : matrix){
			for(int c : r)
				System.out.print(c + "\t");
			System.out.println();
		}
	}
	public int[][] generateMatrix(int n) {
		int[][] matrix = new int[n][n];
		if(n == 0)
			return matrix;
		int l = 0, r = matrix[0].length - 1;
		int u = 0, d = matrix.length - 1;
		int num = 1;
		while (l <= r && u <= d) {
			for (int i = l; i <= r; i++)
				matrix[u][i] = num++;
			u++;
			if (u > d)
				continue;
			for (int i = u; i <= d; i++)
				matrix[i][r] = num++;
			r--;
			if (l > r)
				continue;
			for (int i = r; i >= l; i--)
				matrix[d][i] = num++;
			d--;
			if (u > d)
				continue;
			for (int i = d; i >= u; i--)
				matrix[i][l] = num++;
			l++;
		}
		return matrix;
	}
}
时间: 2024-08-29 05:44:53

LeetCode——Spiral Matrix II的相关文章

LeetCode: Spiral Matrix II [058]

[题目] Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example, Given n = 3, You should return the following matrix: [ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ] [题意] 给定整数n, 将1,2,3...nxn个数按螺旋旋转的方式填入nxn的矩

LeetCode: Spiral Matrix II 解题报告-三种方法解决旋转矩阵问题

Spiral Matrix IIGiven an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example,Given n = 3, You should return the following matrix:[ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ]] SOLUTION 1: 还是与上一题Spiral Matrix类似

leetcode Spiral Matrix II

题目:是Spiral Matrix相关的的.这题的意思是给定一个n,那么在n*n的矩阵里按照循环记录将1,2,3,..., n*n.如下如果给定3,那么: [ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ]一开始我想是不是有数学公式直接下标对应的,那直接遍历输出就可以了.但是推了一会,没有什么好的头绪.于是就分情况讨论了,和Spiral Matrix一样的分情况,只是这里的分情况是记录在数组里面.利用上,下,左,右,分别记录每次循环可以到达的四个边界,我们每次就输

LeetCode Spiral Matrix II (技巧)

题意: 从1开始产生连续的n2个数字,以螺旋的方式填满一个n*n的数组. 思路: 由于是填满一个矩阵,那么只需要每次都填一圈即可.应该注意特殊情况. 迭代: 1 class Solution { 2 public: 3 vector<vector<int> > generateMatrix(int n) 4 { 5 vector<vector<int> > ans(n,vector<int>(n)); 6 int cnt=0, i=0; 7 wh

LeetCode:Spiral Matrix II - 将元素1-n^2以螺旋序填充到矩阵

1.题目名称 Spiral Matrix(螺旋输出矩阵中的元素) 2.题目地址 https://leetcode.com/problems/spiral-matrix-ii/ 3.题目内容 英文:Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. 中文:给出一个整数n,生成一个矩阵,使用数字1到n^2以螺旋顺序填充这个矩阵 例如:给出n=3,则生成如下矩阵:

[LeetCode]59.Spiral Matrix II

[题目] Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example, Given n = 3, You should return the following matrix: [ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ] [分析] 模拟 [代码] /**-------------------------

【LeetCode】Spiral Matrix II

Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example,Given n = 3, You should return the following matrix: [ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ]此题与Spiral Matrix类似,可以用相同的方法解决,相比之下,此题比前一题简单 publ

Spiral Matrix II leetcode java

题目: Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example, Given n = 3, You should return the following matrix: [ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ] 题解:这道题跟Spiral Matrix想法也是类似的,就是依照矩阵从外圈到内圈建立

【leetcode刷题笔记】Spiral Matrix II

Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order. For example,Given n = 3, You should return the following matrix: [ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ] 题解:以前做过的Spiral Matrix是给一个矩阵螺旋式的输出,这道题是给一个n,螺旋式的