将数组中n个整数按相反顺序存放。
解：程序1：
#include<stdio.h>
int inv(int x[], int n)
{
int temp, i, j, m = (n - 1) / 2;
for (i = 0; i <= m; i++)
{
j = n - 1 - i;
temp = x[i];
x[i] = x[j];
x[j] = temp;
}
return;
}
int main()
{
int i, a[10] = { 1,2,3,4,5,6,7,8,9,10 };
printf("The original array:\n");
for (i = 0; i < 10; i++)
{
printf("%d ", a[i]);
}
printf("\n");
inv(a, 10);
printf("The array has been inverted:\n");//inverted:反向的
for (i = 0; i < 10; i++)
{
printf("%d ", a[i]);
}
printf("\n");
return 0;
}
程序2：用指针变量作实参
#include<stdio.h>
int inv(int *x, int n)
{
int *p, temp, *i, *j, m = (n - 1) / 2;
//形参数组名x接收了实参数组首元素a[0]的地址
i = x; j = x + n - 1; p = x + m;
for (; i <= p; i++, j--)
{
temp = *i;
*i = *j;
*j = temp;
}
return;
}
int main()
{
int i, a[10] = { 1,2,3,4,5,6,7,8,9,10 };
printf("The original array:\n");
for (i = 0; i < 10; i++)
{
printf("%d ", a[i]);
}
printf("\n");
inv(a, 10);
printf("The array has been inverted:\n");//inverted:反向的
for (i = 0; i < 10; i++)
{
printf("%d ", a[i]);
}
printf("\n");
return 0;
}
结果：
he original array:
1 2 3 4 5 6 7 8 9 10
The array has been inverted:
10 9 8 7 6 5 4 3 2 1
请按任意键继续. . .