The Mussels
Time Limit: 1000ms
Memory Limit: 32768KB
This problem will be judged on HDU. Original ID: 2439
64-bit integer IO format: %I64d Java class name: Main
"To be or not to be, that is the question." Now FJ( Frank&John) faces a serious problem.
FJ is breeding mussels these days. The mussels all want to be put into a culturist with a grade no little than their own grades. FJ accept their requirements.
FJ provides culturists of different grades, all having a certain capacity. FJ first put mussels into culturists with the same grade until they are full. Then he may put some mussels into some potential culturists that still have capacity.
Now, FJ wants to know how many mussels can be put into the culturists.
Input
For each data set:
The first line contains two integers, n and m(0<n<=100000,0<m<=1000000), indicating the number of culturists and the number of mussels. The ith culturist has a grade i, and grade 1 is considered the highest.
The second line contains n integers indicating the culturists‘ capacity in order.
The third line contains m integers all in the range 1~n, indicating the mussels‘ grade in order.
Proceed to the end of file.
Output
A single integer, which is the number of mussels that can be put into the culturists.
Sample Input
4 4 100 4 4 4 1 2 3 4 4 3 1 1 1 1 4 2 2
Sample Output
4 3
Source
2008 Asia Harbin Regional Contest Online
解题：贪心+模拟，直接按照题目意思去做就是了。。。
1 #include <iostream>
2 #include <cstdio>
3 #include <cstring>
4 #include <cmath>
5 #include <algorithm>
6 #include <climits>
7 #include <vector>
8 #include <queue>
9 #include <cstdlib>
10 #include <string>
11 #include <set>
12 #include <stack>
13 #define LL long long
14 #define pii pair<int,int>
15 #define INF 0x3f3f3f3f
16 using namespace std;
17 int cul[100010],tmp,n,m;
18 void myscanf(int &x){
19 char ch;
20 while((ch = getchar()) < ‘0‘ || ch > ‘9‘);
21 x = 0;
22 x = x*10 + ch - ‘0‘;
23 while((ch = getchar()) >= ‘0‘ && ch <= ‘9‘) x = x*10 + ch - ‘0‘;
24 }
25 int main() {
26 while(~scanf("%d %d",&n,&m)){
27 for(int i = 1; i <= n; i++)
28 myscanf(cul[i]);
29 int ans = 0;
30 for(int i = 1; i <= m; i++){
31 myscanf(tmp);
32 if(cul[tmp]){
33 --cul[tmp];
34 ++ans;
35 }else{
36 for(int j = tmp; j; --j){
37 if(cul[j]){
38 --cul[j];
39 ++ans;
40 break;
41 }
42 }
43 }
44 }
45 printf("%d\n",ans);
46 }
47 return 0;
48 }