A == B ?

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 88211    Accepted Submission(s): 13922

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

Input

each test case contains two numbers A and B.

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

Sample Input

1 2
2 2
3 3
4 3

Sample Output

NO
YES
YES
NO

本以为是一道水题，没想到处处坑点，被坑了一发。。

数组尽量开大一点，注意小数后无意义的0

AC代码：

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 using namespace std;
 5
 6 const int MAX=100000;
 7 char a[MAX]={0},b[MAX]={0};
 8
 9 int main(){
10
11     while(scanf("%s %s",&a,&b)!=EOF){
12         int i=0;
13         if(strchr(a,‘.‘)){//a中是否含小数点
14             for(i=strlen(a)-1;a[i]==‘0‘;i--)
15                 a[i]=‘\0‘;//消掉末尾的0
16                 if(a[i]=‘.‘)
17                 a[i]=‘\0‘;//消掉无意义的小数点
18         }
19         if(strchr(b,‘.‘)){
20             for(i=strlen(b)-1;b[i]==‘0‘;i--)
21                 b[i]=‘\0‘;
22                 if(b[i]=‘.‘)
23                  b[i]=‘\0‘;
24         }
25         printf(strcmp(a,b)?"NO\n":"YES\n");//strcmp函数当a，b相等时返回值为0
26     }
27     return 0;
28 }