模拟,注意需要比较队头与当前时间的大小关系。
1 #include <cstdio> 2 #include <cstring> 3 #include <cstdlib> 4 5 #define MAXN 10005 6 #define INF 0xffffff 7 8 typedef struct { 9 int i, t; 10 } node_t; 11 12 13 node_t Q[2][MAXN]; 14 int buf[MAXN]; 15 int rear[2], front[2]; 16 17 int main() { 18 int case_n; 19 int n, t, m; 20 int i, j, k, a; 21 int d; 22 char s[7]; 23 24 #ifndef ONLINE_JUDGE 25 freopen("data.in", "r", stdin); 26 freopen("data.out", "w", stdout); 27 #endif 28 29 scanf("%d", &case_n); 30 for (a=0; a<case_n; ++a) { 31 scanf("%d %d %d", &n, &t, &m); 32 rear[0] = rear[1] = 0; 33 front[0] = front[1] = 0; 34 for (i=1; i<=m; ++i) { 35 scanf("%d %s", &k, s); 36 if (s[0] == ‘l‘) 37 j = 0; 38 else 39 j = 1; 40 Q[j][rear[j]].i = i; 41 Q[j][rear[j]].t = k; 42 rear[j]++; 43 } 44 Q[0][rear[0]].t = INF; 45 Q[1][rear[1]].t = INF; 46 d = 0; 47 int ans = 0; 48 while (front[0]<rear[0] || front[1]<rear[1]) { 49 if (Q[d][front[d]].t>ans && Q[!d][front[!d]].t<=ans) { 50 ans += t; 51 d = !d; 52 } else if ((Q[d][front[d]].t>Q[!d][front[!d]].t || front[d]>=rear[d]) && Q[!d][front[!d]].t>ans) { 53 ans = Q[!d][front[!d]].t + t; 54 d = !d; 55 } 56 if (ans < Q[d][front[d]].t) 57 ans = Q[d][front[d]].t; 58 j = 0; 59 i = front[d]; 60 while (j<n && i<rear[d] && Q[d][i].t<=ans) { 61 buf[Q[d][i].i] = ans + t; 62 ++j; 63 ++i; 64 } 65 ans += t; 66 front[d] = i; 67 d = !d; 68 } 69 if (a) 70 printf("\n"); 71 for (i=1; i<=m; ++i) 72 printf("%d\n", buf[i]); 73 } 74 75 return 0; 76 }
时间: 2024-10-04 22:30:36