1 #include <iostream> 2 #include <queue> 3 #include <stack> 4 #include <cstdio> 5 #include <vector> 6 #include <map> 7 #include <set> 8 #include <bitset> 9 #include <algorithm> 10 #include <cmath> 11 #include <cstring> 12 #include <cstdlib> 13 #include <string> 14 #include <sstream> 15 #include <time.h> 16 #define x first 17 #define y second 18 #define pb push_back 19 #define mp make_pair 20 #define lson l,m,rt*2 21 #define rson m+1,r,rt*2+1 22 #define mt(A,B) memset(A,B,sizeof(A)) 23 using namespace std; 24 typedef long long LL; 25 typedef unsigned long long ull; 26 //const double PI = acos(-1); 27 const int N=3e3+10; 28 const LL mod=1e9+7; 29 const int inf = 0x3f3f3f3f3f; 30 const LL INF=0x3f3f3f3f3f3f3f3fLL; 31 const double eps=1e-8; 32 LL dp[300][20][2][2]; 33 int num[300]; 34 char s[300]; 35 LL dfs(int pos,int pre,int limit,int flag,int zero) 36 { 37 LL res=0; 38 if(pos<0) 39 { 40 if(zero)return 0; 41 else return 1; 42 } 43 if(!limit&&dp[pos][pre][flag][zero]!=-1)return dp[pos][pre][flag][zero]; 44 45 int top=limit?num[pos]:9; 46 if(zero) 47 { 48 for(int i=0;i<=top;i++) 49 { 50 res=(res+dfs(pos-1,i,limit&&(num[pos]==i),0,i==0))%mod; 51 } 52 } 53 else 54 { 55 if(flag) 56 { 57 for(int i=pre;i<=top;i++) 58 { 59 res=(res+dfs(pos-1,i,limit&&(num[pos]==i),1,0))%mod; 60 } 61 } 62 else 63 { 64 for(int i=min(pre,top);i>=0;i--) 65 { 66 res=(res+dfs(pos-1,i,limit&&(num[pos]==i),0,0))%mod; 67 } 68 for(int i=pre+1;i<=top;i++) 69 { 70 res=(res+dfs(pos-1,i,limit&&(num[pos]==i),1,0))%mod; 71 } 72 } 73 } 74 75 if(!limit)dp[pos][pre][flag][zero]=res; 76 return res; 77 } 78 void solve() 79 { 80 int n; 81 mt(dp,-1); 82 scanf("%s",s); 83 n=strlen(s); 84 for(int i=n-1,j=0;i>=0;i--,j++)num[j]=s[i]-‘0‘; 85 printf("%lld\n",dfs(n-1,0,1,0,1)); 86 } 87 int main() 88 { 89 #ifdef Local 90 freopen("data.h","r",stdin); 91 //freopen("out.txt","w",stdout); 92 #endif 93 //ios::sync_with_stdio(false); 94 //cin.tie(0); 95 //solve(); 96 int T,cas=1; 97 cin>>T; 98 while(T--) 99 { 100 //printf("Case #%d: ",cas++); 101 solve(); 102 } 103 #ifdef Local 104 cerr << "time: " << (LL) clock() * 1000 / CLOCKS_PER_SEC << " ms" << endl; 105 #endif 106 return 0; 107 }
时间: 2024-10-12 08:58:10