首先我们来构造几个map集合。
假设如下代码 都是在ssh配置环境下搭建好,(至少struts2开发环境搭建好)
(1).java 代码
下面的student对象包含的字段为
private Long id; private String num; private String name; private String sex; private Integer age;
Action中的代码
private Map<String,String> map; private Map<String,Student> studentMap; private Map<String,String[]> arrayMap; private Map<String,List<Student>> listMap; // 实现 四个map对象的get 和set方法。 map=new HashMap<String,String>(); map.put("1", "one"); map.put("2", "two"); studentMap=new HashMap<String,Student>(); studentMap.put("student1",new Student(new Long(1),"20034140201","张三1","男",25)); studentMap.put("student2",new Student(new Long(2),"20034140202","张三2","女",26)); studentMap.put("student3",new Student(new Long(3),"20034140202","张三3","男",27)); arrayMap=new HashMap<String,String[]>(); arrayMap.put("arr1", new String[]{"1","2003401","leejie","male","20"}); arrayMap.put("arr2", new String[]{"2","2003402","huanglie","male","25"}); arrayMap.put("arr3", new String[]{"3","2003403","lixiaoning","male","21"}); listMap=new HashMap<String,List<Student>>(); List<Student> list1=new ArrayList<Student>(); list1.add(new Student(new Long(1),"20034140201","张三1","男",25)); list1.add(new Student(new Long(2),"20034140202","张三2","男",25)); list1.add(new Student(new Long(3),"20034140203","张三3","男",25)); listMap.put("class1", list1); List<Student> list2=new ArrayList<Student>(); list2.add(new Student(new Long(1),"20034140301","李四1","男",20)); list2.add(new Student(new Long(2),"20034140302","李四2","男",21)); list2.add(new Student(new Long(3),"20034140303","李四3","男",22)); list2.add(new Student(new Long(4),"20034140304","李四4","男",23)); listMap.put("class2", list2);
(2).通过上述java代码我们已经构建好了4个map集合。 接下来的重头戏就是如何通过strut2的标签来获取map集合中的值。
1.map中的value为String字符串
<s:iterator value="map" id="column"> <s:property value="#column"/><br> //这里获取到的值为key=value 即:键值对 key: <s:property value="key"/><br> //这里的key为内置的,我们只要在value中写上key 即会有值 value:<s:property value="value"/><br> //同样这里的value也为内置的 </s:iterator> <b>2.map中的value为Student对象</b> <s:iterator value="studentMap" id="column"> <tr> <td><s:property value="#column"/></td> <td><s:property value="key"/></td> <td><s:property value="value"/></td> //这里的value返回的是一个student对象 <td><s:property value="value.id"/></td> //这里获取student对象中的属性值 <td><s:property value="value.num"/></td> <td><s:property value="value.name"/></td> <td><s:property value="value.sex"/></td> <td><s:property value="value.age"/></td> </tr> </s:iterator>
遍历studentMap 还可以用下面方式,跟上面方式效果是一样的
2.map中的value为Student对象
<s:iterator value="studentMap" id="column"> <tr> <td><s:property value="#column"/></td> <td><s:property value="key"/></td> <s:iterator value="value"> <td><s:property value="id"/></td> <td><s:property value="num"/></td> <td><s:property value="name"/></td> <td><s:property value="sex"/></td> <td><s:property value="age"/></td> </s:iterator> </tr> </s:iterator>
3.map中的value为String数组
<s:iterator value="arrayMap" id="column"> <tr> <td><s:property value="#column"/></td> <!--同时取出键和值--> <td><s:property value="value[0]"/></td> <td><s:property value="value[1]"/></td> <td><s:property value="value[2]"/></td> <td><s:property value="value[3]"/></td> <td><s:property value="value[4]"/></td> </tr> </s:iterator>
4.map中的value为list集合
<s:iterator value="listMap" id="column"> <s:set name="total" value="#column.value.size"/> //注意<s:set 标签的用法 <s:iterator value="#column.value" status="s"> //这里#column.value 还是一个student的list集合,因而需要再次迭代一次 <tr> <s:property value="#s.first"/> //判断是不是集合中的第一个对象 <s:if test="#s.first"> <td rowspan="${total}"> <s:property value="#column.key"/> </td> </s:if> <td><s:property value="id"/></td> <td><s:property value="num"/></td> <td><s:property value="name"/></td> <td><s:property value="sex"/></td> <td><s:property value="age"/></td> </tr> </s:iterator> </s:iterator>
时间: 2024-11-03 05:41:40