HDU 3037 Saving Beans (Lucas法则)

主题链接:

pid=3037">http://acm.hdu.edu.cn/showproblem.php?pid=3037

推出公式为C(n + m, m) % p。 用Lucas定理求大组合数取模的值

代码:

#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;

int t;
long long n, m, p;

long long pow(long long n, long long k) {
    if (k == 0) return 1;
    if (k == 1) return n;
    long long ans = pow(n * n % p, k>>1);
    if (k&1) ans = ans * n % p;
    return ans;
}

long long C(long long n, long long m) {
    if (m > n) return 0;
    m = min(m, n - m);
    long long zi = 1, mu = 1;
    for (long long i = 0; i < m; i++) {
	zi = zi * (n - i) % p;
	mu = mu * (i + 1) % p;
    }
    return zi * pow(mu, p - 2) % p;
}

long long Lucas(long long n, long long m, long long p) {
    if (m == 0) return 1;
    return C(n % p, m % p) * Lucas(n / p, m / p, p) % p;
}

int main() {
    scanf("%d", &t);
    while (t--) {
	scanf("%lld%lld%lld", &n, &m, &p);
	printf("%lld\n", Lucas(n + m, m, p));
    }
    return 0;
}

版权声明:本文博主原创文章,博客,未经同意不得转载。

时间: 2024-10-05 23:45:58

HDU 3037 Saving Beans (Lucas法则)的相关文章

[ACM] hdu 3037 Saving Beans (Lucas定理,组合数取模)

Saving Beans Problem Description Although winter is far away, squirrels have to work day and night to save beans. They need plenty of food to get through those long cold days. After some time the squirrel family thinks that they have to solve a probl

HDU 3037 Saving Beans (Lucas定理)

/*求在n棵树上摘不超过m颗豆子的方案,结果对p取模. 求C(n+m,m)%p. 因为n,m很大,这里可以直接套用Lucas定理的模板即可. Lucas(n,m,p)=C(n%p,m%p,p)*Lucas(n/p,m/p,p): ///这里可以采用对n分段递归求解, Lucas(x,0,p)=1: 将n,m分解变小之后问题又转换成了求C(a/b)%p. 而C(a,b) =a! / ( b! * (a-b)! ) mod p 其实就是求 ( a! / (a-b)!) * ( b! )^(p-2)

HDU 3037 Saving Beans(Lucas定理的直接应用)

解题思路: 直接求C(n+m , m) % p , 由于n , m ,p都非常大,所以要用Lucas定理来解决大组合数取模的问题. #include <string.h> #include <iostream> #include <algorithm> #include <vector> #include <queue> #include <set> #include <map> #include <string&g

HDU 3037 Saving Beans (Lucas定理)

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3037 推出公式为C(n + m, m) % p, 用Lucas定理求大组合数取模的值 代码: #include <stdio.h> #include <string.h> #include <algorithm> using namespace std; int t; long long n, m, p; long long pow(long long n, long lo

HDU 3037 Saving Beans(lucas定理)

题目大意:豆子数i (1~m)分到n颗树上.  树可以为空,那么对于每个i,分配方式是 C(n+i-1,n-1)......于是我用for(i=0-->m)做,不幸超时,m太大. 不过竟然公式可以化简: for(int i=0;i<=m;i++) C(n+i-1,n-1)=C(n+i-1,i) 组合原理: 公式 C(n,k) = C(n-1,k)+C(n-1,k-1) C(n-1,0)+C(n,1)+...+C(n+m-1,m) = C(n,0)+C(n,1)+C(n+1,2)+...+C(n

hdu 3037 Saving Beans(组合数学)

hdu 3037 Saving Beans 题目大意:n个数,和不大于m的情况,结果模掉p,p保证为素数. 解题思路:隔板法,C(nn+m)多选的一块保证了n个数的和小于等于m.可是n,m非常大,所以用到Lucas定理. #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long long ll; ll n, m, p; ll qPow (ll a

hdu 3037 Saving Beans 组合数取模模板题。。

Saving Beans Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2707    Accepted Submission(s): 1014 Problem Description Although winter is far away, squirrels have to work day and night to save b

HDU 3037 Saving Beans 多重集合的结合 lucas定理

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3037 题目描述: 要求求x1 + x2 + x3 + ...... + xn <= m 非负整数解的个数, 结果对P取模, 输入的变量是n, m, p, P一定是素数 解题思路: x1 + ... + xn = m 非负整数解的个数是C(n+m-1, n) , 所以答案就是 C(n+0-1, 0) + C(n+1-1, 1) + ...... C(n+m-1, n) 对P取模, 由于组合数公式C(

HDU 3037 Saving Beans(Lucas定理模板题)

Problem Description Although winter is far away, squirrels have to work day and night to save beans. They need plenty of food to get through those long cold days. After some time the squirrel family thinks that they have to solve a problem. They supp