Clone an undirected graph. Each node in the graph contains a label
and a list of its neighbors
.
OJ‘s undirected graph serialization:
Nodes are labeled uniquely.
We use #
as a separator for each node, and ,
as
a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by #
.
- First node is labeled as
0
. Connect node0
to
both nodes1
and2
. - Second node is labeled as
1
. Connect node1
to
node2
. - Third node is labeled as
2
. Connect node2
to
node2
(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1 / / 0 --- 2 / \_/
复制无向带环图。
思路:按照深度搜索递归遍历每个顶点,遍历结果是返回以临界点为起始点的子图。要考虑带环的情况,又要避免同一节点访问多次,可用map来判重。
static class UndirectedGraphNode { int label; List<UndirectedGraphNode> neighbors; UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); } } static public UndirectedGraphNode dfs(UndirectedGraphNode node, Map<Integer, UndirectedGraphNode> vis) { if (node != null && vis.get(node.label) == null) { UndirectedGraphNode cloneNode = new UndirectedGraphNode(node.label); vis.put(node.label, cloneNode); cloneNode.neighbors = new ArrayList<UndirectedGraphNode>(node.neighbors.size()); for (int i = 0; i < node.neighbors.size(); i++) { cloneNode.neighbors.add(dfs(node.neighbors.get(i), vis)); } return cloneNode; } else if (node == null) { return node; } else { //deal if the graph has a circle return vis.get(node.label); } } static public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) { Map<Integer, UndirectedGraphNode> vis = new HashMap<Integer, UndirectedGraphNode>(); return dfs(node, vis); } public static void main(String[] args) { UndirectedGraphNode node = new UndirectedGraphNode(0); node.neighbors.add(node); System.out.println(node.neighbors.get(0) == node); UndirectedGraphNode clone = cloneGraph(node); System.out.println(clone.label); }
时间: 2024-11-08 08:56:01