CF 548A Mike and Fax

Descripe

While Mike was walking in the subway, all the stuff in his back-bag dropped on the ground. There were several fax messages among them. He concatenated these strings in some order and now he has string s.

He is not sure if this is his own back-bag or someone else‘s. He remembered that there were exactly k messages in his own bag, each was a palindrome string and all those strings had the same length.

He asked you to help him and tell him if he has worn his own back-bag. Check if the given string s is a concatenation of k palindromes of the same length.

Input

The first line of input contains string s containing lowercase English letters (1 ≤ |s| ≤ 1000).

The second line contains integer k (1 ≤ k ≤ 1000).

Output

Print "YES"(without quotes) if he has worn his own back-bag or "NO"(without quotes) otherwise.

Sample test(s)

Input

saba2

Output

NO

Input

saddastavvat2

Output

YES

Note

Palindrome is a string reading the same forward and backward.

In the second sample, the faxes in his back-bag can be "saddas" and "tavvat".

CODE:

#include <iostream>
#include <cstdio>
#include <cstring>
#define REP(i, s, n) for(int i = s; i <= n; i ++)
#define REP_(i, s, n) for(int i = n; i >= s; i --)
#define MAX_N 1000 + 10

using namespace std;

char ts[MAX_N], s[MAX_N];
int len[MAX_N], k;

bool check(int l, int r){
    int i = l, j = r;
    bool tmp = 1;
    while(i < j){
        if(s[i] != s[j]){
            tmp = 0; break;
        }
        i ++; j --;
    }
    if(tmp) return true;
    return false;
}

int main(){
    scanf("%s", s + 1); scanf("%d", &k);
    int l = strlen(s + 1);
    if(l % k != 0){printf("NO\n"); return 0;}
    int num = l / k;

    int i = 1; bool ok = 1;
    while(i < l){
        if(!check(i, i + num - 1)) ok = 0;
        i += num;
    }

    if(ok) printf("YES\n");
    else printf("NO\n");

    return 0;
}