careercup-1.1

1.1 实现一个算法,确定一个字符串的所有字符是否全部不同。假设不允许使用额外的数据结构,又该如何处理?

C++实现:

#include<iostream>
#include<string>
#include<cstring>
using namespace std;

/*
判断是否有重复字符
*/
bool unqString(string s)
{
    if(s.empty())
        return true;
    int n=s.length();
    int word[256]={0};
    int i;
    for(i=0;i<n;i++)
        word[s[i]]++;
    for(i=0;i<n;i++)
        if(word[s[i]]>1)
            return false;
    return true;
}
int main()
{
    string str="asdhfdsf";
    cout<<unqString(str)<<endl;
}

使用关联容器set:

#include<set>
#include<string>
using namespace std;

bool unqString(string s)
{
    set<char> st;
    if(s.empty())
        return false;
    size_t i;
    for(i=0;i<s.length();i++)
        st.insert(s[i]);
    if(st.size()!=s.length())
        return false;
    else
        return true;
}

int main()
{
    string str="asdhf";
    cout<<unqString(str)<<endl;
}
时间: 2024-10-07 16:19:58

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