Given an array nums
, write a function to move all 0
‘s to the end of it while maintaining the relative order of the non-zero elements.
For example, given nums = [0, 1, 0, 3, 12]
, after calling your function, nums
should be [1, 3, 12, 0, 0]
.
Note:
- You must do this in-place without making a copy of the array.
- Minimize the total number of operations.
从后往前遍历,为0的数和后面所有的数交换,复杂度为n2
一刷:
public void moveZeroes(int[] nums) { int zeros=0; for (int i = nums.length - 1; i >= 0; i--) { if (nums[i] == 0){ for (int j = i; j < nums.length - 1 ; j++) { nums[j] = nums[j+1]; } nums[nums.length-zeros-1] = 0; zeros += 1; } } }
时间: 2024-10-08 23:45:44