今天要说的是给List分组，然后用Map来封装，可能你看了以后还是有一些模糊。
先看一下项目结构图：
User类是一个VO类，主要逻辑还是在MapTestBak上面。
运行效果：
原理图：
1.在starsList中有两组人，共三人
2.在dolList中有一组人，共两人
3.经过marched操作，最后匹配到一组人到result中。即第一组人。
原理很简单。
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源码部分：
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/mapTest/src/com/b510/map/MapTestBak.java
1 /**
2 *
3 */
4 package com.b510.map;
5
6 import java.util.ArrayList;
7 import java.util.HashMap;
8 import java.util.List;
9 import java.util.Map;
10
11 /**
12 * @author Hongten
13 * @created Apr 28, 2014
14 */
15 public class MapTestBak {
16
17 public static void main(String[] args) {
18 mapTest();
19 }
20
21 /**
22 *
23 */
24 private static void mapTest() {
25 // starsList
26 List<User> starsList = getStarsList();
27
28 // dolList
29 List<User> dolList = getDolList();
30
31 Map<String, List<User>> map = groupingHandler(starsList);
32 // test
33 groupingHandlerTest(map);
34
35 System.out.println("======= group finished =======");
36 List<Map<String, List<User>>> compareResultList = compare(dolList, map);
37 if(null != compareResultList){
38 System.out.println(compareResultList.size());
39 }
40 }
41
42 /**
43 * @param dolList
44 * @param map
45 */
46 private static List<Map<String, List<User>>> compare(List<User> dolList, Map<String, List<User>> map) {
47 List<Map<String, List<User>>> tempList = new ArrayList<Map<String, List<User>>>();
48 if (null != map) {
49 for (String key : map.keySet()) {
50 List<User> u = map.get(key);
51 List comList = new ArrayList();
52 boolean comFlag = true;
53 for (User us : u) {
54 List comList1 = new ArrayList();
55 for (User ul : dolList) {
56 if (us.getGroupNO() == ul.getGroupNO() && us.getName().trim().equals(ul.getName().trim())) {
57 comList1.add(1);
58 } else {
59 comList1.add(0);
60 }
61 }62 if (comList1.contains(1)) {
63 // name has existed.
64 comList.add(1);
65 } else {
66 comList.add(0);
67 }
68 }
69 if (comList.contains(0)) {
70 comFlag = false;
71 }
72 // print out the match result in the console.
73 printMatchResult(tempList, key, u, comFlag);
74 }
75 }else{
76 System.out.println("map is null!");
77 }
78 return tempList;
79 }
80
81 /**
82 * @param tempList
83 * @param key
84 * @param u
85 * @param comFlag
86 */
87 private static void printMatchResult(List<Map<String, List<User>>> tempList, String key, List<User> u, boolean comFlag) {
88 if (comFlag) {
89 // do something
90 System.out.println("group : " + key + " compared!\n Detail:");
91 System.out.println("================");
92 for (User ut : u) {
93 System.out.println(ut.getGroupNO() + ", " + ut.getName());
94 }
95 System.out.println("================");
96 Map<String, List<User>> tempMap = new HashMap<String, List<User>>();
97 tempMap.put(key, u);
98 tempList.add(tempMap);
99 } else {
100 System.out.println("group : " + key + " NOT compared!");
101 }
102 }
103
104 /**
105 * @param map
106 */
107 private static void groupingHandlerTest(Map<String, List<User>> map) {
108 if (null != map) {
109 for (String key : map.keySet()) {
110 List<User> u = map.get(key);
111 for (User u1 : u) {
112 System.out.println(u1.getGroupNO() + ", " + u1.getName());
113 }
114 }
115 }
116 }
117
118 /**
119 * @param starsList
120 * @param map
121 */
122 private static Map<String, List<User>> groupingHandler(List<User> starsList) {
123 Map<String, List<User>> map = new HashMap<String, List<User>>();
124 for (User stars_user : starsList) {
125 String no = String.valueOf(stars_user.getGroupNO());
126 if (map.isEmpty()) {
127 List<User> l = new ArrayList<User>();
128 l.add(stars_user);
129 map.put(no, l);
130 } else {
131 List<User> user_map = map.get(no);
132 if (null == user_map || "".equals(user_map)) {
133 List<User> l = new ArrayList<User>();
134 l.add(stars_user);
135 map.put(no, l);
136 } else {
137 List<User> l = map.get(no);
138 l.add(stars_user);
139 map.put(no, l);
140 }
141 }
142 }
143 return map;
144 }
145
146 /**
147 * @param dolList
148 */
149 private static List<User> getDolList() {
150 List<User> dolList = new ArrayList<User>();
151 User user_B1_dol = new User(1, "MRS KON");
152 User user_A_dol = new User(1, "KON SUE");
153 dolList.add(user_B1_dol);
154 dolList.add(user_A_dol);
155 return dolList;
156 }
157
158 /**
159 * @param starsList
160 */
161 private static List<User> getStarsList() {
162 List<User> starsList = new ArrayList<User>();
163 User user_B1 = new User(1, "MRS KON");
164 User user_A = new User(1, "KON SUE");
165 User user_B2 = new User(2, "MRS KON");
166 User user_C = new User(2, "LON MEI");
167 starsList.add(user_B1);
168 starsList.add(user_A);
169 starsList.add(user_B2);
170 starsList.add(user_C);
171 return starsList;
172 }
173 }
/mapTest/src/com/b510/map/User.java
1 /**
2 *
3 */
4 package com.b510.map;
5
6 /**
7 * @author Hongten
8 * @created Apr 28, 2014
9 */
10 public class User {
11
12 private int groupNO;
13 private String name;
14
15 public int getGroupNO() {
16 return groupNO;
17 }
18
19 public User(int groupNO, String name) {
20 this.groupNO = groupNO;
21 this.name = name;
22 }
23
24 public void setGroupNO(int groupNO) {
25 this.groupNO = groupNO;
26 }
27
28 public String getName() {
29 return name;
30 }
31
32 public void setName(String name) {
33 this.name = name;
34 }
35
36 }
我想要记录一下的是方法：compare(List<User> dolList, Map<String,
List<User>> map)
1 private static List<Map<String, List<User>>> compare(List<User> dolList, Map<String, List<User>> map) {
2 List<Map<String, List<User>>> tempList = new ArrayList<Map<String, List<User>>>();
3 if (null != map) {
4 for (String key : map.keySet()) {
5 List<User> u = map.get(key);
6 List comList = new ArrayList();
7 boolean comFlag = true;
8 for (User us : u) {
9 List comList1 = new ArrayList();
10 for (User ul : dolList) {
11 if (us.getGroupNO() == ul.getGroupNO() && us.getName().trim().equals(ul.getName().trim())) {
12 comList1.add(1);
13 } else {
14 comList1.add(0);
15 }
16 }
17 if (comList1.contains(1)) {
18 // name has existed.
19 comList.add(1);
20 } else {
21 comList.add(0);
22 }
23 }
24 if (comList.contains(0)) {
25 comFlag = false;
26 }
27 // print out the match result in the console.
28 printMatchResult(tempList, key, u, comFlag);
29 }
30 }else{
31 System.out.println("map is null!");
32 }
33 return tempList;
34 }
在这个方法中，这里使用了两个List（即：comList, comList1）来记录是否完全匹配。
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多读一些书，英语很重要。
More reading,and english is important.
I‘m Hongten
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java中的List记录是否完全匹配方法,码迷,mamicode.com