Description
This is a true story. A man showed his love to a girl,but the girl didn‘t replied clearly ,just gave him a Morse Code:
****-/*----/----*/****-/****-/*----/---**/*----/****-/*----/-****/***--/****-/*----/----*/**---/-****/**---/**---/***--/--***/****-/ He was so anxious that he asked for help in the Internet and after one day a girl named "Pianyi angel" found the secret of this code. She translate this code as this five steps:
1.First translate the morse code to a number string: 4194418141634192622374
2.Second she cut two number as one group 41 94 41 81 41 63 41 92 62 23 74,according to standard Mobile phone can get this alphabet:GZGTGOGXNCS
3.Third she change this alphabet according to the keyboard: QWERTYUIOPASDFGHJKLZXCVBNM = ABCDEFGHIJKLMNOPQRSTUVWXYZ
So ,we can get OTOEOIOUYVL
4.Fourth, divide this alphabet to two parts: OTOEOI and OUYVL, compose again.we will get OOTUOYEVOLI
5.Finally,reverse this alphabet the answer will appear : I LOVE YOU TOO
I guess you might worship Pianyi angel as me,so let‘s Orz her.
Now,the task is translate the number strings.
Input
A number string each line(length <= 1000). I ensure all input are legal.
Output
An upper alphabet string.
Sample Input
4194418141634192622374
41944181416341926223
Sample Output
ILOVEYOUTOO
VOYEUOOTIO
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<queue>
using namespace std;
int main()
{
char ss[1314],s[1314];
char* a[]={"ABC","DEF","GHI","JKL","MNO","PQRS","TUV","WXYZ"};
char b[]="KXVMCNOPHQRSZYIJADLEGWBUFT";
char d[]="QWERTYUIOPASDFGHJKLZXCVBNM";
//for(int i=0;i<26;i++)
// cout<<b[d[i]-‘A‘]<<" ";
while(gets(ss))
{
int m=strlen(ss);
int len=0;
for(int i=0;i<m;i++)
if(ss[i]!=‘ ‘)
s[len++]=ss[i];
char s0[520];
int x=0;
for(int i=0;i<len;i+=2)
{
s0[x++]=b[a[s[i]-‘2‘][s[i+1]-‘1‘]-‘A‘];
}
char s1[520];
int y=0;
for(int i=0;i<x;i+=2)
{
s1[i]=s0[y++];
}
for(int i=1;i<x;i+=2)
{
s1[i]=s0[y++];
}
for(int i=y-1;i>=0;i--)
{
putchar(s1[i]);
}
printf("\n");
}
}