PAT 乙级 1014

　　本题主要还是考验细致程度，需要把各种情况考虑到、题审清楚

  1 #include <iostream>
  2 #include <string>
  3 using namespace std;
  4
  5 int main() {
  6     string str[4];
  7     for (int i = 0; i < 4; i++)
  8         getline(cin, str[i]);
  9     int str_1 = 0, str_2 = 0;
 10     str_1 = str[0].size();
 11     str_2 = str[1].size();
 12     int len = 0;
 13     if (str_1 > str_2)
 14         len = str_2;
 15     else len = str_1;
 16     int cnt = 0;
 17     for (int i = 0; i < len; i++) {
 18         if (str[0][i] == str[1][i]) {
 19             char tmp = str[0][i];
 20             if (cnt == 0 && tmp >= ‘A‘ && tmp <= ‘G‘) {
 21                 cnt++;
 22                 switch(tmp) {
 23                 case ‘A‘:
 24                     cout << "MON ";
 25                     break;
 26                 case ‘B‘:
 27                     cout << "TUE ";
 28                     break;
 29                 case ‘C‘:
 30                     cout << "WED ";
 31                     break;
 32                 case ‘D‘:
 33                     cout << "THU ";
 34                     break;
 35                 case ‘E‘:
 36                     cout << "FRI ";
 37                     break;
 38                 case ‘F‘:
 39                     cout << "SAT ";
 40                     break;
 41                 case ‘G‘:
 42                     cout << "SUN ";
 43                     break;
 44                 }
 45             }
 46             else if (cnt == 1 && (isdigit(tmp) || tmp >= ‘A‘ && tmp <= ‘N‘)) {
 47                 cnt++;
 48                 switch(tmp) {
 49                 case ‘0‘:
 50                     cout << "00:";
 51                     break;
 52                 case ‘1‘:
 53                     cout << "01:";
 54                     break;
 55                 case ‘2‘:
 56                     cout << "02:";
 57                     break;
 58                 case ‘3‘:
 59                     cout << "03:";
 60                     break;
 61                 case ‘4‘:
 62                     cout << "04:";
 63                     break;
 64                 case ‘5‘:
 65                     cout << "05:";
 66                     break;
 67                 case ‘6‘:
 68                     cout << "06:";
 69                     break;
 70                 case ‘7‘:
 71                     cout << "07:";
 72                     break;
 73                 case ‘8‘:
 74                     cout << "08:";
 75                     break;
 76                 case ‘9‘:
 77                     cout << "09:";
 78                     break;
 79                 case ‘A‘:
 80                     cout << "10:";
 81                     break;
 82                 case ‘B‘:
 83                     cout << "11:";
 84                     break;
 85                 case ‘C‘:
 86                     cout << "12:";
 87                     break;
 88                 case ‘D‘:
 89                     cout << "13:";
 90                     break;
 91                 case ‘E‘:
 92                     cout << "14:";
 93                     break;
 94                 case ‘F‘:
 95                     cout << "15:";
 96                     break;
 97                 case ‘G‘:
 98                     cout << "16:";
 99                     break;
100                 case ‘H‘:
101                     cout << "17:";
102                     break;
103                 case ‘I‘:
104                     cout << "18:";
105                     break;
106                 case ‘J‘:
107                     cout << "19:";
108                     break;
109                 case ‘K‘:
110                     cout << "20:";
111                     break;
112                 case ‘L‘:
113                     cout << "21:";
114                     break;
115                 case ‘M‘:
116                     cout << "22:";
117                     break;
118                 case ‘N‘:
119                     cout << "23:";
120                     break;
121                 }
122             }
123         }
124         if (cnt > 1)
125             break;
126     }
127     str_1 = str[2].size();
128     str_2 = str[3].size();
129     if (str_1 > str_2)
130         len = str_2;
131     else len = str_1;
132     for (int i = 0; i < len; i++) {
133         if (str[2][i] == str[3][i] && ((str[2][i] >= ‘a‘ && str[2][i] <= ‘z‘) || (str[2][i] >= ‘A‘ && str[2][i] <= ‘Z‘))) {
134             if (i < 10)
135                 cout << "0" << i << endl;
136             else
137                 cout << i << endl;
138             break;
139         }
140     }
141
142     return 0;
143 }

原文地址：https://www.cnblogs.com/moujun1001/p/9351400.html