使用通配符来解决数据1和11、12/13/14的问题

update FOURxiaozhang set President23_1 = ‘1‘ WHERE President23 like ‘1|%‘;
update FOURxiaozhang set President23_1 = ‘1‘ WHERE President23 = ‘1‘;
update FOURxiaozhang set President23_2 = ‘1‘ WHERE President23 like ‘%[^1]2%‘;
update FOURxiaozhang set President23_3 = ‘1‘ WHERE President23 like ‘%[^1]3%‘;
update FOURxiaozhang set President23_4 = ‘1‘ WHERE President23 like ‘%[^1]4%‘;
update FOURxiaozhang set President23_5 = ‘1‘ WHERE President23 like ‘%[^1]5%‘;
update FOURxiaozhang set President23_6 = ‘1‘ WHERE President23 like ‘%[^1]6%‘;
update FOURxiaozhang set President23_7 = ‘1‘ WHERE President23 like ‘%7%‘;
update FOURxiaozhang set President23_8 = ‘1‘ WHERE President23 like ‘%8%‘;
update FOURxiaozhang set President23_9 = ‘1‘ WHERE President23 like ‘%9%‘;
update FOURxiaozhang set President23_10 = ‘1‘ WHERE President23 like ‘%10%‘;
update FOURxiaozhang set President23_11 = ‘1‘ WHERE President23 like ‘%11%‘;
update FOURxiaozhang set President23_12 = ‘1‘ WHERE President23 like ‘%12%‘;
update FOURxiaozhang set President23_13= ‘1‘ WHERE President23 like ‘%13%‘;

时间： 2024-10-20 01:21:12

使用通配符来解决数据1和11、12/13/14的问题的相关文章

多线程-线程一打印1,2,3,4,5线程二打印6,7,8,9,10,线程三打印11,12,13,14,15,...直到45结束

多线程-线程一打印1,2,3,4,5线程二打印6,7,8,9,10,线程三打印11,12,13,14,15,...知道45结束 public class Exam3{ public static void main(String[]args){ MyThread t1=new MyThread("线程一"); MyThread t2=new MyThread("线程二"); MyThread t3=new MyThread("线程三"); t1.

剑指offer19：按照从外向里以顺时针的顺序依次打印出每一个数字，4 X 4矩阵： 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.

1 题目描述输入一个矩阵,按照从外向里以顺时针的顺序依次打印出每一个数字,例如,如果输入如下4 X 4矩阵: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10. 2 思路和方法直接定义一个矩形,在矩形的四条边取值,程序大大简化. 3 核心代码 1 class Solution { 2 public: 3 vector<int> printMatrix(vector<

一个嵌套很多层的列表，如l=［1,2,[3,[4,5,6,[7,8,[9,10,[11,12,13,[14,15]]]]]]］，用递归取出所有的值

'''一个嵌套很多层的列表,如l=［1,2,[3,[4,5,6,[7,8,[9,10,[11,12,13,[14,15]]]]]]］,用递归取出所有的值''' l=[1,2,[3,[4,5,6,[7,8,[9,10,[11,12,13,[14,15]]]]]]] def get(seq): for item in seq: if type(item) is list: get(item) else: print(item) get(l) 原文地址:https://www.cnblogs.com/

11 12 13 14 py单引号字符串、双引号字符串和转义符字符串拼接保持字符串的原汁原味

第11课单引号字符串.双引号字符串和转义符 # 单引号字符串.双引号字符串和转义符 print('Hello World') print("Hello World") print("Let's go!") print('"OK"') print("'H',\"W\"") -------------------------- 输出结果 Let's go! "OK" 'H',"W

已知如下数组： var arr = [ [1, 2, 2], [3, 4, 5, 5], [6, 7, 8, 9, [11, 12, [12, 13, [14] ] ] ], 10]; 编写一个程序将数组扁平化去并除其中重复部分数据，最终得到一个升序且不重复的数组

已知如下数组: var arr = [ [1, 2, 2], [3, 4, 5, 5], [6, 7, 8, 9, [11, 12, [12, 13, [14] ] ] ], 10]; 编写一个程序将数组扁平化去并除其中重复部分数据,最终得到一个升序且不重复的数组 var dt= arr.toString().split(",").sort(function(a,b){return a-b}).map(Number);Array.from(new Set(dt)) 代码如下 var d

使用通配符来解决数据1和11、12/13/14的问题