如果项目中有评论或者信息恢复的地方,往往会用到emoji,有时候如后台不支持emoji,就会显示乱码错误,我们可以把emoji转成unicode编码或者utf8编码格式传给服务器。当然如果后台服务器接收的时候能做好判断识别最好,我们这边后台是支持的,我仅记录一下方法,以备不时之需。
先定义一个UITextView 并设置代理
设定一个宏定义,用来判断emoji
#define MULITTHREEBYTEUTF16TOUNICODE(x,y) (((((x ^ 0xD800) << 2) | ((y ^ 0xDC00) >> 8)) << 8) | ((y ^ 0xDC00) & 0xFF)) + 0x10000
下面写代理方法实现的内容
1 - (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text 2 { 3 NSString *hexstr = @""; 4 5 for (int i=0;i< [text length];i++) 6 { 7 hexstr = [hexstr stringByAppendingFormat:@"%@",[NSString stringWithFormat:@"0x%1X ",[text characterAtIndex:i]]]; 8 } 9 NSLog(@"UTF16 [%@]",hexstr); 10 11 hexstr = @""; 12 13 long slen = strlen([text UTF8String]); 14 15 for (int i = 0; i < slen; i++) 16 { 17 //fffffff0 去除前面六个F & 0xFF 18 hexstr = [hexstr stringByAppendingFormat:@"%@",[NSString stringWithFormat:@"0x%X ",[text UTF8String][i] & 0xFF ]]; 19 } 20 NSLog(@"UTF8 [%@]",hexstr); 21 22 hexstr = @""; 23 24 if ([text length] >= 2) { 25 26 for (int i = 0; i < [text length] / 2 && ([text length] % 2 == 0) ; i++) 27 { 28 // three bytes 29 if (([text characterAtIndex:i*2] & 0xFF00) == 0 ) { 30 hexstr = [hexstr stringByAppendingFormat:@"Ox%1X 0x%1X",[text characterAtIndex:i*2],[text characterAtIndex:i*2+1]]; 31 } 32 else 33 {// four bytes 34 hexstr = [hexstr stringByAppendingFormat:@"U+%1X ",MULITTHREEBYTEUTF16TOUNICODE([text characterAtIndex:i*2],[text characterAtIndex:i*2+1])]; 35 } 36 37 } 38 NSLog(@"(unicode) [%@]",hexstr); 39 } 40 else 41 { 42 NSLog(@"(unicode) U+%1X",[text characterAtIndex:0]); 43 } 44 45 return YES; 46 }
在输入的时候,会自动把输入内容转成相应的格式。
如果在有些地方不需要输入emoji表情,可以做相关限制。
我这边用到的是,如果用户输入emoji表情的时候,会给出提示
1 //是否含有表情 2 - (BOOL)stringContainsEmoji:(NSString *)string 3 { 4 __block BOOL returnValue = NO; 5 6 [string enumerateSubstringsInRange:NSMakeRange(0, [string length]) 7 options:NSStringEnumerationByComposedCharacterSequences 8 usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) { 9 const unichar hs = [substring characterAtIndex:0]; 10 if (0xd800 <= hs && hs <= 0xdbff) { 11 if (substring.length > 1) { 12 const unichar ls = [substring characterAtIndex:1]; 13 const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000; 14 if (0x1d000 <= uc && uc <= 0x1f77f) { 15 returnValue = YES; 16 } 17 } 18 } else if (substring.length > 1) { 19 const unichar ls = [substring characterAtIndex:1]; 20 if (ls == 0x20e3) { 21 returnValue = YES; 22 } 23 } else { 24 if (0x2100 <= hs && hs <= 0x27ff) { 25 returnValue = YES; 26 } else if (0x2B05 <= hs && hs <= 0x2b07) { 27 returnValue = YES; 28 } else if (0x2934 <= hs && hs <= 0x2935) { 29 returnValue = YES; 30 } else if (0x3297 <= hs && hs <= 0x3299) { 31 returnValue = YES; 32 } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50) { 33 returnValue = YES; 34 } 35 } 36 }]; 37 38 return returnValue; 39 }
通过调用该方法,如果返回的是YES则输入内容含有emoji,反之。
时间: 2024-10-11 10:51:14