Given an integer n, generate a square matrix filled with elements from 1 to n2 in
spiral order.
For example,
Given n = 3
,
You should return the following matrix:
[ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ]
思路:与上一篇类似。仅仅要不越界就ok
public class Solution { public int[][] generateMatrix(int n) { if (n == 0) return new int[0][0]; int[][] matrix = new int[n][n]; int x1 = 0; int y1 = 0; int x2 = matrix.length - 1; int y2 = matrix[0].length - 1; int i = 0, j = 1; while (x1 <= x2 && y1 <= y2) { // up row for (i = y1; i <= y2; ++i, j++) matrix[x1][i] = j; // right column for (i = x1 + 1; i <= x2; ++i, j++) matrix[i][y2] = j; // bottom row for (i = y2 - 1; x2 != x1 && i >= y1; --i, j++) matrix[x2][i] = j; // left column for (i = x2 - 1; y1 != y2 && i > x1; --i, j++) matrix[i][y1] = j; x1++; y1++; x2--; y2--; } return matrix; } }
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时间: 2024-11-19 08:07:36