趣味图形之 二次函数与圆相交

先看看它像什么？？？？！

好吧(∩_∩)，它像，，，，很多，发挥自己的创意去组合吧

1.

/***二次函数与圆最完美图像***/
#include <stdio.h>
#include <math.h>

int main (void)
{
    int m, n, x;
    double y;
    for ( y = 20; y >= -10; y-- )
    {
        if ( y > 10 )
        {
            m = 1.8 * sqrt(y);
            for ( x = 1; x <= 40; x++ )
            {
                if ( x == 20 - m || x == 20 + m )
                    printf ( "*" );
                else
                    printf (" ");
            }
        }
        else if ( y >= 0 && y <= 10 )
        {
            m = 1.8 * sqrt ( y );
            n = 1.8 * sqrt ( 100 - y * y );
            for ( x = 1; x <= 40; x++ )
            {
                if ( x == 20 - m && x == 20 - n || x == 20 + m && x == 20 + n )
                    printf ("+");
                else if ( x == 20 - m || x == 20 - n || x == 20 + m || x == 20 + n )
                    printf ("*");
                else
                    printf (" ");
            }
        }
        else
        {
            n = 1.8 * sqrt ( 100 - y * y );
            for ( x = 1; x <= 40; x++ )
            {
                if ( x == 20 - n || x == 20 + n )
                    printf ("*");
                else
                    printf (" ");
            }
        }
        printf ("\n");
    }
    return 0;
}

2.

/***二次函数与圆的叠加显示2***/
# include <stdio.h>
# include <math.h>
int main (void)
{
    int x, m, n;
    double y;
    for (y = 10; y >= 0; y--)
    {
        m = 1.8 * sqrt( y );
        n = 1.8 * sqrt( 100 - y * y );
        for ( x = 1; x <= 40; x++ )
        {
            if ( (x == 20 - m) && (x == 20 - n) || (x == 20 + m) && (x == 20 + n) )
                printf ("+");
            else if ( (x == 20 - m) || (x == 20 - n) || (x == 20 + m) || (x == 20 + n) )
                printf ("*");
            else
                printf (" ");
        }
        printf ("\n");
    }
    for ( y = 0; y >= -10; y-- )
    {
        n = 1.8 * sqrt( 100 - y * y );
        for ( x = 1; x <= 40; x++ )
        {
            if ( x == 20 - n || x == 20 + n )
                printf ("*");
            else
                printf (" ");
        }
        printf ( "\n" );
    }
    return 0;
}

运行之后(和第一个不同，要注意的是，屏幕的长宽比不一样)

3.

/***二次函数与圆的叠加显示3***/
# include <stdio.h>
# include <math.h>
int main (void)
{
    int m, n;
    double y;
    for ( y = 10; y >= -10; y-- )
    {
        m = 1.8 * sqrt ( abs(y) );
        n = 1.8 * sqrt ( 100 - y * y );
        for ( int x = 0; x <= 40; x++ )
        {
            if ( (x == 20 - m) && (x == 20 - n) || ( x == 20 + m ) && ( x == 20 + n ) )
                printf ( "+" );
            else if ( (x == 20 - m) || (x == 20 - n) || ( x == 20 + m ) || ( x == 20 + n ) )
                printf ( "*" );
            else
                printf ( " " );
        }
        printf ( "\n" );
    }
    return 0;
}

运行之后

图片超神般存在