指针与多维数组深度剖析

源码

[[email protected] ch10]# cat zippo11.c

/* zippo1.c --  zippo info */

#include <stdio.h>

int main(void)

{

int b[3]={100,200,300}; int *p;p=b;

printf("b=%p,*b=%d,p=%p,*p=%d,p+1=%p,*p+1=%d \n",b,*b,p,*p,p+1,*p+1);

printf("---------------------------\n");

int zippo[4][2] = { {2,4}, {6,8}, {1,3}, {5, 7} };

printf("   zippo = %p,    zippo + 1 = %p\n",

zippo,         zippo + 1);

printf("zippo[0] = %p, zippo[0] + 1 = %p\n",

zippo[0],      zippo[0] + 1);

printf("  *zippo = %p,   *zippo + 1 = %p\n",

*zippo,        *zippo + 1);

printf("zippo[0][0] = %d\n", zippo[0][0]);

printf("  *zippo[0] = %d\n", *zippo[0]);

printf("    **zippo = %d\n", **zippo);

printf("      zippo[2][1] = %d\n", zippo[2][1]);

printf("*(*(zippo+2)) = %d\n", *(*(zippo+2)));

printf("*(*(zippo+2) + 1) = %d\n", *(*(zippo+2) + 1));

printf("---------------------------\n");

printf("*(*(zippo+1)) = %d\n", *(*(zippo+1)));

printf("*(*(zippo+1) + 1) = %d\n", *(*(zippo+1) + 1));

printf("*(*(zippo)) = %d\n", *(*(zippo)));

printf("*(*(zippo)+1) = %d\n", *(*(zippo)+1));

return 0;

}

结果：

[[email protected] ch10]# ./zippo11

b=0xbfda6dd0,*b=100,p=0xbfda6dd0,*p=100,p+1=0xbfda6dd4,*p+1=101

---------------------------

zippo = 0xbfda6db0,    zippo + 1 = 0xbfda6db8

zippo[0] = 0xbfda6db0, zippo[0] + 1 = 0xbfda6db4

*zippo = 0xbfda6db0,   *zippo + 1 = 0xbfda6db4

zippo[0][0] = 2

*zippo[0] = 2

**zippo = 2

zippo[2][1] = 3

*(*(zippo+2)) = 1

*(*(zippo+2) + 1) = 3

---------------------------

*(*(zippo+1)) = 6

*(*(zippo+1) + 1) = 8

*(*(zippo)) = 2

*(*(zippo)+1) = 4

指针与多维数组深度剖析