【leetcode】988. Smallest String Starting From Leaf

题目如下：

Given the root of a binary tree, each node has a value from 0 to 25representing the letters ‘a‘ to ‘z‘: a value of 0 represents ‘a‘, a value of 1 represents ‘b‘, and so on.

Find the lexicographically smallest string that starts at a leaf of this tree and ends at the root.

(As a reminder, any shorter prefix of a string is lexicographically smaller: for example, "ab" is lexicographically smaller than "aba".  A leaf of a node is a node that has no children.)

Example 1:

Input: [0,1,2,3,4,3,4]
Output: "dba"

Example 2:

Input: [25,1,3,1,3,0,2]
Output: "adz"

Example 3:

Input: [2,2,1,null,1,0,null,0]
Output: "abc"

Note:

1. The number of nodes in the given tree will be between 1 and 1000.
2. Each node in the tree will have a value between 0 and 25.

解题思路：把树遍历一下就好了，依次记录从根节点开始每一层的节点的值，到达叶子节点后比较得到最小值。

代码如下：

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
    res = ‘z‘*1001
    def recursive(self,node,path):
        path += chr(node.val + ord(‘a‘))
        if node.left == None and node.right == None:
            self.res = min(self.res,path[::-1])
        if node.left != None:
            self.recursive(node.left,path)
        if node.right != None:
            self.recursive(node.right, path)

    def smallestFromLeaf(self, root):
        """
        :type root: TreeNode
        :rtype: str
        """
        if root != None:
            self.recursive(root,‘‘)
        return self.res

原文地址：https://www.cnblogs.com/seyjs/p/10353719.html