IDA打开。Main()函数就是关键算法
v6,v7,v8 是连续的 。可看成 L=[16,32,48]。输入的name每位分别于L[]异或 得到的值存在v13。然后清空v9的值 ,输入Serial储存在v9 再让v13与v9比较。
可还原算法:
#!usr/bin/env python #!coding=utf-8 __author__ = ‘zhengjim‘ name = raw_input() L=[16,32,48] flag =‘‘ for i,name in enumerate(name): f = hex(ord(name)^L[i%3]).replace(‘0x‘,‘‘) flag+=f print flag.upper()
暴力破解代码:
#!usr/bin/env python #!coding=utf-8 __author__ = ‘zhengjim‘ S = [0x5B,0x13,0x49,0x77,0x13,0x5E,0x7D,0x13] L=[16,32,48] flag =‘‘ for i,s in enumerate(S): for f in xrange(127): if f^L[i%3] == s: flag+=chr(f) break print flag
时间: 2024-12-27 08:26:55