在view中实现UIViewController的跳转

view中是不能进行UIViewController的push，pop等操作的，若进行跳转操作，一般是用代理，block,通知等实现，那如何实现在ViewController的subView中实现跳转操作呢，其实只要获取该view所在的ViewController即可。

获取view所在UIViewController

UIView+UIViewController.h

#import <UIKit/UIKit.h>

@interface UIView (UIViewController)

- (UIViewController *)viewController;

@end

UIView+UIViewController.m

#import "UIView+UIViewController.h"

@implementation UIView (UIViewController)

- (UIViewController *)viewController {

    //通过响应者链，获得view所在的视图控制器
    UIResponder *next = self.nextResponder;
    do {
        //判断响应者对象是否是视图控制器类型
        if ([next isKindOfClass:[UIViewController class]]) {
            return (UIViewController *)next;
        }
        next = next.nextResponder;
    }while(next != nil);

    return nil;
}

@end

or

- (UIViewController *)viewController {
    // Traverse responder chain. Return first found view controller, which will be the view‘s view controller.
    UIResponder *responder = self;
    while ((responder = [responder nextResponder]))
        if ([responder isKindOfClass: [UIViewController class]])
            return (UIViewController *)responder;

    return nil;
}

- (UIViewController*)viewController {
    for (UIView* next = [self superview]; next; next = next.superview) {
        UIResponder* nextResponder = [next nextResponder];
        if ([nextResponder isKindOfClass:[UIViewController class]]) {
            return (UIViewController*)nextResponder;
        }
    }
    return nil;
}

使用：

在subview中导入  #import "UIView+UIViewController.h"

-(void)viewDidSelect
{
    WebViewController *vc = [[WebViewController alloc] init];
    vc.webUrl [email protected]"http://www.baidu.com"；
    [self.viewController.navigationController pushViewController:vc animated:YES];
}