小记：按两次返回键退出应用程序。

 1 private long exitTime = 0;
 2     @Override
 3     public boolean onKeyDown(int keyCode, KeyEvent event) {
 4
 5         if (keyCode == KeyEvent.KEYCODE_BACK
 6                 && event.getAction() == KeyEvent.ACTION_DOWN) {
 7             if ((System.currentTimeMillis() - exitTime) > 2000) { // System.currentTimeMillis()无论何时调用，肯定大于2000
 8
 9                 Toast.makeText(getApplicationContext(), "再按一次退出程序",
10                         Toast.LENGTH_SHORT).show();
11                 exitTime = System.currentTimeMillis();
12             } else {
13                 finish();
14                 System.exit(0);
15             }
16             return true;
17         }
18         return super.onKeyDown(keyCode, event);
19     }