leetcode-Maximum Subarray-53

最大子串和，输入一个数组，求连续的元素和的最大值

ans保存最大值，sum保存包含当前元素的前一个元素的连续子串的和，如果sum<0说明对当前元素来说是负影响，所以sum=0，然后加到当前元素；如果sum>=0说明是正影响，加到当前元素。更新答案。ON

 1 class Solution {
 2 public:
 3     int maxSubArray(vector<int>& nums) {
 4         if(nums.size()==0) return 0;
 5         int ans=nums[0];
 6         int sum=nums[0];
 7         for(int i=1;i<nums.size();i++){
 8             if(sum<0){
 9                 sum=0;
10             }
11             sum+=nums[i];
12             ans=max(sum,ans);
13         }
14         return ans;
15     }
16 };

时间： 2024-12-28 09:02:42

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