A+B Coming

Problem Description

Many classmates said to me that A+B is must needs.
If you can’t AC this problem, you would invite me for night meal.
^_^

Input

Input may contain multiple test cases. Each case
contains A and B in one line.
A, B are hexadecimal number.
Input
terminates by EOF.

Output

Output A+B in decimal number in one line.

Sample Input

1 9

A B

a b

Sample Output

10

21

21

 1 #include <stdio.h>
 2 #include <string.h>
 3 #include <ctype.h>
 4 #include <math.h>
 5
 6 int decimal(char s[]);
 7
 8 int main(){
 9     char s1[50];
10     char s2[50];
11     int number1;
12     int number2;
13
14     while(scanf("%s%s",s1,s2)!=EOF){
15         number1=decimal(s1);
16         number2=decimal(s2);
17
18         printf("%d\n",number1+number2);
19
20     }
21
22     return 0;
23 }
24
25 int decimal(char s[]){
26     int result=0;
27     int i;
28     int length;
29     int temp;
30
31     length=strlen(s);
32
33     for(i=length-1;i>=0;i--){
34         if(isdigit(s[i]))
35             temp=s[i]-‘0‘;
36
37         else if(s[i]==‘A‘ || s[i]==‘a‘)
38             temp=10;
39
40         else if(s[i]==‘B‘ || s[i]==‘b‘)
41             temp=11;
42
43         else if(s[i]==‘C‘ || s[i]==‘c‘)
44             temp=12;
45
46         else if(s[i]==‘D‘ || s[i]==‘d‘)
47             temp=13;
48
49         else if(s[i]==‘E‘ || s[i]==‘e‘)
50             temp=14;
51
52         else if(s[i]==‘F‘ || s[i]==‘f‘)
53             temp=15;
54
55         result+=temp*pow(16,length-1-i);
56     }
57
58     return result;
59 }