Keep on Truckin‘

Problem Description

Boudreaux and Thibodeaux are on the road again . . .

"Boudreaux, we have to get this shipment of mudbugs to Baton Rouge by tonight!"

"Don‘t worry, Thibodeaux, I already checked ahead. There are three underpasses and our 18-wheeler will fit through all of them, so just keep that motor running!"

"We‘re not going to make it, I say!"

So, which is it: will there be a very messy accident on Interstate 10, or is Thibodeaux just letting the sound of his own wheels drive him crazy?

Input

Input to this problem will consist of a single data set. The data set will be formatted according to the following description.

The data set will consist of a single line containing 3 numbers, separated by single spaces. Each number represents the height of a single underpass in inches. Each number will be between 0 and 300 inclusive.

Output

There will be exactly one line of output. This line will be:

NO CRASH

if the height of the 18-wheeler is less than the height of each of the underpasses, or:

CRASH X

otherwise, where X is the height of the first underpass in the data set that the 18-wheeler is unable to go under (which means its height is less than or equal to the height of the 18-wheeler). 
The height of the 18-wheeler is 168 inches.

Sample Input

180 160 170

Sample Output

CRASH 160

分析：无脑判断。

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<cstdlib>
 4 #include<iostream>
 5 using namespace std;
 6 int main()
 7 {
 8     int a,b,c;
 9     scanf("%d%d%d",&a,&b,&c);
10     if(a<=168) printf("CRASH %d\n",a);
11     else if(b<=168) printf("CRASH %d\n",b);
12     else if(c<=168) printf("CRASH %d\n",c);
13     else printf("NO CRASH\n");
14     return 0;
15 }