281. Zigzag Iterator

题目:

Given two 1d vectors, implement an iterator to return their elements alternately.

For example, given two 1d vectors:

v1 = [1, 2]
v2 = [3, 4, 5, 6]

By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1, 3, 2, 4, 5, 6].

Follow up: What if you are given k 1d vectors? How well can your code be extended to such cases?

Clarification for the follow up question - Update (2015-09-18):
The "Zigzag" order is not clearly defined and is ambiguous for k > 2 cases. If "Zigzag" does not look right to you, replace "Zigzag" with "Cyclic". For example, given the following input:

[1,2,3]
[4,5,6,7]
[8,9]

It should return [1,4,8,2,5,9,3,6,7].

链接: http://leetcode.com/problems/zigzag-iterator/

题解:

Zigzag Iterator。最简单的就是用两个index分别遍历两个list,然后用一个boolean变量来控制何时遍历哪一个list。 好像我这么做是有问题的,应该用Interator<>来做。

Time Complexity - O(n), Space Complexity - O(1)

public class ZigzagIterator {
    private int length;
    private int index1 = 0;
    private int index2 = 0;
    private List<Integer> list1;
    private List<Integer> list2;
    private boolean useList2;

    public ZigzagIterator(List<Integer> v1, List<Integer> v2) {
        this.length = v1.size() + v2.size();
        list1 = v1;
        list2 = v2;
        if(list1.size() == 0) {
            useList2 = true;
        }
    }

    public int next() {
        if(!useList2) {
            if(index2 < list2.size()) {
                useList2 = true;
            }
            return list1.get(index1++);
        } else {
            if(index1 < list1.size()) {
                useList2 = false;
            }
            return list2.get(index2++);
        }

    }

    public boolean hasNext() {
        return (index1 + index2) < length;
    }
}

/**
 * Your ZigzagIterator object will be instantiated and called as such:
 * ZigzagIterator i = new ZigzagIterator(v1, v2);
 * while (i.hasNext()) v[f()] = i.next();
 */

Reference:

https://leetcode.com/discuss/57961/o-n-time-%26-o-1-space-java-solution

https://leetcode.com/discuss/63037/simple-java-solution-for-k-vector

https://leetcode.com/discuss/58012/short-java-o-1-space

https://leetcode.com/discuss/71857/clean-java-solution-works-for-k-lists

时间: 2024-10-28 11:49:18

281. Zigzag Iterator的相关文章

[LeetCode#281] Zigzag Iterator

Problem: Given two 1d vectors, implement an iterator to return their elements alternately. For example, given two 1d vectors: v1 = [1, 2] v2 = [3, 4, 5, 6] By calling next repeatedly until hasNext returns false, the order of elements returned by next

281. Zigzag Iterator z字型遍历

[抄题]: Given two 1d vectors, implement an iterator to return their elements alternately. Example: Input: v1 = [1,2] v2 = [3,4,5,6] Output: [1,3,2,4,5,6] Explanation: By calling next repeatedly until hasNext returns false,   the order of elements retur

281. Zigzag Iterator - Medium

Given two 1d vectors, implement an iterator to return their elements alternately. Example: Input: v1 = [1,2] v2 = [3,4,5,6] Output: [1,3,2,4,5,6] Explanation: By calling next repeatedly until hasNext returns false,   the order of elements returned by

Leetcode: Zigzag Iterator

Given two 1d vectors, implement an iterator to return their elements alternately. For example, given two 1d vectors: v1 = [1, 2] v2 = [3, 4, 5, 6] By calling next repeatedly until hasNext returns false, the order of elements returned by next should b

Zigzag Iterator

Given two 1d vectors, implement an iterator to return their elements alternately. For example, given two 1d vectors: v1 = [1, 2] v2 = [3, 4, 5, 6] By calling next repeatedly until hasNext returns false, the order of elements returned by next should b

leetcode 锁掉的题目清单

也刷leetcode, 先把锁掉的题目留备份好了: 156 Binary Tree Upside Down  [1] Problem: Given a binary tree where all the right nodes are either leaf nodes with a sibling (a left node that shares the same parent node) or empty, flip it upside down and turn it into a tre

过中等难度题目.0310

  .   8  String to Integer (atoi)    13.9% Medium   . 151 Reverse Words in a String      15.7% Medium     . 288 Unique Word Abbreviation      15.8% Medium     . 29 Divide Two Integers      16.0% Medium     . 166 Fraction to Recurring Decimal      17.

继续过中等难度.0309

  .   8  String to Integer (atoi)    13.9% Medium   . 151 Reverse Words in a String      15.7% Medium     . 288 Unique Word Abbreviation      15.8% Medium     . 29 Divide Two Integers      16.0% Medium     . 166 Fraction to Recurring Decimal      17.

LeetCode Problems List 题目汇总

No. Title Level Rate 1 Two Sum Medium 17.70% 2 Add Two Numbers Medium 21.10% 3 Longest Substring Without Repeating Characters Medium 20.60% 4 Median of Two Sorted Arrays Hard 17.40% 5 Longest Palindromic Substring Medium 20.70% 6 ZigZag Conversion Ea