题目描述:
You‘re given strings J
representing the types of stones that are jewels, and S
representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J
are guaranteed distinct, and all characters in J
and S
are letters. Letters are case sensitive, so "a"
is considered a different type of stone from "A"
.
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
S
andJ
will consist of letters and have length at most 50.- The characters in
J
are distinct.
解题思路:
此题难度为easy,遍历S中每个letter s并判断s是否在J中存在,若存在个数加一。
代码:
1 class Solution { 2 public: 3 int numJewelsInStones(string J, string S) { 4 int num = 0; 5 for (auto s : S) { 6 if (J.find(s) != string::npos) 7 num++; 8 } 9 return num; 10 } 11 };
原文地址:https://www.cnblogs.com/gsz-/p/9373834.html
时间: 2024-11-08 07:18:46