main函数的实现解析

main函数的传参的实现，其实也是一个解析字符串的过程：将每个word后一个空格改为“/0”,将单词提取出来。

就是这么简单。

废话不多说，直接上代码：

 1 #include<stdio.h>
 2 #include<string.h>
 3 void shell_parse(char *sbuf)
 4 {
 5 char mbuf[50];
 6 sprintf(mbuf,"%s",sbuf);
 7     char *buf=mbuf;//两次转换，得到一个能++的指针
 8
 9     //strcpy(a,buf);
10     int i;
11     int argc=0;
12     char *argv[8];
13     int state = 0;
14     while(*buf)
15     {
16         char c = *buf;
17         printf("%c\n",c);
18         if(c == ‘ ‘ &&state==0)
19             state = 0;
20         if(c!= ‘ ‘&& state ==0)
21         {
22             argv[argc++] =buf;
23             state = 1;
24             printf("1:::argv[%d]:%s\n",argc,argv[0]);
25         }
26         if(c == ‘ ‘&&state == 1)
27         {
28             *buf = ‘\0‘;
29             state = 0;
30         }
31     /*    if(c !=‘ ‘&& state == 0)
32         {
33             argv[argc++] = buf;
34             printf("2::argv[%d]:%s\n",argc,argv[argc]);
35             state = 1;
36
37         }*/
38         buf++;
39         if(*buf == ‘\n‘)
40         *buf = ‘\0‘;
41
42     }
43         argv[argc] = NULL;
44
45         printf("argc = %d\n",argc);
46         for(i = 0;i<=argc;i++)
47         {
48             printf("argv[%d]:%s\n",i,argv[i]);
49         }
50 //        free((void*)buf);
51 }
52 int main(int argc,char **argv)
53 {
54     int i = 0;
55     char buf[64];
56 //fgets(buf,64,stdin);
57 //printf("buf = %s\n",buf);
58     sprintf(buf,"%s","hsfsfs fsf fsaf;fsa fsfd");
59     printf("hell");
60     shell_parse("fsjf  sflsdjf dsfsfsdf fs");//此处实现完全传出来的是参数。
61
62 }
63