Fri Oct 31 18:00:00 UTC+0800 2008转换为yyyy-mm-dd

这个其实网上有很多例子，都是直接用js在前端做了时间处理，我的处理也一样，想要变成2008-3-31，就用下面的js直接可以处理

    function Todate(num) { //Fri Oct 31 18:00:00 UTC+0800 2008
        num = num + "";
        var date = "";
        var month = new Array();
        month["Jan"] = 1; month["Feb"] = 2; month["Mar"] = 3; month["Apr"] = 4; month["May"] = 5; month["Jun"] = 6;
        month["Jul"] = 7; month["Aug"] = 8; month["Sep"] = 9; month["Oct"] = 10; month["Nov"] = 11; month["Dec"] = 12;
        var week = new Array();
        week["Mon"] = "一"; week["Tue"] = "二"; week["Wed"] = "三"; week["Thu"] = "四"; week["Fri"] = "五"; week["Sat"] = "六"; week["Sun"] = "日";
        str = num.split(" ");
        date = str[5] + "-";
        date = date + month[str[1]] + "-" + str[2];//获取到的年月日，要是想加上时分秒，就date = date + month[str[1]] + "-" + str[2]+ " " + str[3];
        return date;
    }

我正好做项目，时间要转换成2008-03，我就直接加了个判断

function spliceZero(param)
		{
		    if (param < 10) {
		    param = "0" + param;
		}
		    return param;
		} 

/***  下面给个完整的例子***/

function Todate(num) { //Fri Oct 31 18:00:00 UTC+0800 2008            if(num!=""){                num = num + "";                var date = "";                var month = new Array();                month["Jan"] = 1; month["Feb"] = 2; month["Mar"] = 3; month["Apr"] = 4; month["May"] = 5; month["Jun"] = 6;                month["Jul"] = 7; month["Aug"] = 8; month["Sep"] = 9; month["Oct"] = 10; month["Nov"] = 11; month["Dec"] = 12;                str = num.split(" ");                date = str[5] + "-";                date = date + spliceZero(month[str[1]]);                return date;            }else{                 return "";            }                    }                function spliceZero(param)        {            if (param < 10) {            param = "0" + param;        }            return param;        }