- 主要是由于页面可能不是通过 request.sendRedirect跳转的,可能通过js location跳转的。所以需要拿跳转后的 地址,重新发送请求。。。如下所示
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if (status == HttpStatus.SC_MOVED_PERMANENTLY || status == HttpStatus.SC_MOVED_TEMPORARILY) { Header locationHeader = hm.getResponseHeader("location"); String location = null; if (locationHeader != null) { location = locationHeader.getValue(); GetMethod redirect=new GetMethod(location); int status_ = http.executeMethod(redirect); if (status_ != HttpStatus.SC_OK) { throw new JobExecutionException("[执行结果=失败][状态码=" + status + "]" + (hm.getStatusLine() == null ? "" : "[信息=" + hm.getStatusText() + "]")); } //responseBody = getPostResponse(location, parts);// 用跳转后的页面重新请求。 } } else if (status == HttpStatus.SC_OK) { responseBody = hm.getResponseBodyAsString(); }else{ //非正常执行,异常处理代码。。 }
时间: 2024-10-30 01:17:17