POJ 3481 Double Queue(STL)

题意  模拟银行的排队系统  有三种操作  1-加入优先级为p 编号为k的人到队列  2-服务当前优先级最大的   3-服务当前优先级最小的  0-退出系统

能够用stl中的map   由于map本身就依据key的值排了序   相应2。3  我们仅仅须要输出最大或最小即可了并从map中删除该键值

#include<cstdio>
#include<map>
using namespace std;
map<int, int> a;
int main()
{
    map<int, int>::iterator it;
    int n,k,p;
    while (scanf ("%d", &n), n)
    {
        if (n == 1)
        {
            scanf ("%d%d", &k, &p);
            a[p] = k;
        }
        else
        {
            if (a.empty()) printf ("0\n");
            else
            {
                if(n==2) it = a.end(),--it;
                else it=a.begin();
                printf ("%d\n", it->second);
                a.erase (it->first);
            }
        }
    }
    return 0;
}

Double Queue

Description

The new founded Balkan Investment Group Bank (BIG-Bank) opened a new office in Bucharest, equipped with a modern computing environment provided by IBM Romania, and using modern information technologies. As usual, each client
of the bank is identified by a positive integer K and, upon arriving to the bank for some services, he or she receives a positive integer priority P. One of the inventions of the young managers of the bank shocked the software engineer of
the serving system. They proposed to break the tradition by sometimes calling the serving desk with the lowest priority instead of that with the highest priority. Thus, the system will receive the following types of request:

0 The system needs to stop serving
K P Add client K to the waiting list with priority P
2 Serve the client with the highest priority and drop him or her from the waiting list
3 Serve the client with the lowest priority and drop him or her from the waiting list

Your task is to help the software engineer of the bank by writing a program to implement the requested serving policy.

Input

Each line of the input contains one of the possible requests; only the last line contains the stop-request (code 0). You may assume that when there is a request to include a new client in the list (code 1), there is no other
request in the list of the same client or with the same priority. An identifier K is always less than 106, and a priority P is less than 107. The client may arrive for being served multiple times, and each time may obtain
a different priority.

Output

For each request with code 2 or 3, the program has to print, in a separate line of the standard output, the identifier of the served client. If the request arrives when the waiting list is empty, then the program prints zero
(0) to the output.

Sample Input

2
1 20 14
1 30 3
2
1 10 99
3
2
2
0

Sample Output

0
20
30
10
0
时间: 2024-10-16 19:49:43

POJ 3481 Double Queue(STL)的相关文章

poj 3481 Double Queue STL中map的运用

题意: 维护一个集合,操作有1:加入一个元素,2:删除最大元素,3:删除最小元素. 分析: map本质是个容器,且具有第一个关键字有序的性质,所以用它来水水就好啦~ 代码: //poj 3481 //sep9 #include <iostream> #include <map> using namespace std; map<int,int> mymap; map<int,int>::iterator iter; int main() { int x,su

POJ - 3481 - Double Queue (STL)

Double Queue Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11133   Accepted: 5056 Description The new founded Balkan Investment Group Bank (BIG-Bank) opened a new office in Bucharest, equipped with a modern computing environment provid

AVL树(模板题)—— POJ 3481 Double Queue

对应POJ题目:点击打开链接 Double Queue Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11741   Accepted: 5335 Description The new founded Balkan Investment Group Bank (BIG-Bank) opened a new office in Bucharest, equipped with a modern computing env

POJ 3481 Double Queue(Treap模板题)

Double Queue Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 15786   Accepted: 6998 Description The new founded Balkan Investment Group Bank (BIG-Bank) opened a new office in Bucharest, equipped with a modern computing environment provid

跳跃表基础——POJ 3481 Double Queue

对应POJ 题目:点击打开链接 Double Queue Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11768   Accepted: 5349 Description The new founded Balkan Investment Group Bank (BIG-Bank) opened a new office in Bucharest, equipped with a modern computing en

POJ 3481 Double Queue 堆修改标记

Enemy Double Queue! 题目大意:维护一种数据结构,支持以下操作: 1.插入一个值 2.查询最大值并删除 3.查询最小值并删除 元素的值<=1000W 这数据结构一看就是堆...不过堆结构不能同时维护最大值和最小值,于是我们开两个堆,一个大根堆,一个小根堆 其中一堆删除时,另一堆也要删除相应元素 于是删除的话有两种方法 1.映射 1000W开数组映射妥妥MLE 于是我们在两个堆之间互相映射 不太好写 pair里开自己的指针会报错,于是只能开了void* 不过速度还是很可观的 #i

POJ 3481 Double Queue(set实现)

Double Queue The new founded Balkan Investment Group Bank (BIG-Bank) opened a new office in Bucharest, equipped with a modern computing environment provided by IBM Romania, and using modern information technologies. As usual, each client of the bank

POJ 3481 Double Queue splay

题意:3个炒作,1 插入一个(值,优先级) 2  找优先级最大的输出值并删除  3,找优先值最小的输出值并删除. 解题思路:splay 解题代码: 1 // File Name: poj3481.cpp 2 // Author: darkdream 3 // Created Time: 2015年04月09日 星期四 14时41分43秒 4 5 #include<vector> 6 #include<list> 7 #include<map> 8 #include<

POJ 题目3481 Double Queue(SBT ro map)

Double Queue Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11824   Accepted: 5385 Description The new founded Balkan Investment Group Bank (BIG-Bank) opened a new office in Bucharest, equipped with a modern computing environment provid