题意:给定两个队伍的每个人的得分,让你安排怎么比赛才能使得观众知道冠军的时间最长。
析:贪心,很简单,就是先开始总分高的先出最差劲的,总分低的先出最厉害的,这个题当时实在是读的不明白啊,WA了好多次。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <map> #include <cctype> #include <cmath> #include <stack> #include <sstream> #define debug() puts("++++"); #define gcd(a, b) __gcd(a, b) #define lson l,m,rt<<1 #define rson m+1,r,rt<<1|1 #define freopenr freopen("in.txt", "r", stdin) #define freopenw freopen("out.txt", "w", stdout) using namespace std; typedef long long LL; typedef unsigned long long ULL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const LL LNF = 1e16; const double inf = 0x3f3f3f3f3f3f; const double PI = acos(-1.0); const double eps = 1e-8; const int maxn = 1e5 + 10; const int mod = 1e9 + 7; const int dr[] = {-1, 0, 1, 0}; const int dc[] = {0, 1, 0, -1}; const char *de[] = {"0000", "0001", "0010", "0011", "0100", "0101", "0110", "0111", "1000", "1001", "1010", "1011", "1100", "1101", "1110", "1111"}; int n, m; const int mon[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; const int monn[] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m; } struct Node{ int id, val; bool operator < (const Node &p) const{ return val < p.val; } }; vector<Node> v1, v2; int main(){ cin >> n; int sum1 = 0, sum2 = 0; for(int i = 1; i <= n; ++i){ scanf("%d", &m); v1.push_back((Node){i, m}); sum1 += m; } for(int i = 1; i <= n; ++i){ scanf("%d", &m); v2.push_back((Node){i, m}); sum2 += m; } sort(v1.begin(), v1.end()); sort(v2.begin(), v2.end()); if(sum1 > sum2) for(int i = 0; i < n; ++i) printf("%d %d\n", v1[i].id, v2[n-i-1].id); else for(int i = 0; i < n; ++i) printf("%d %d\n", v1[n-i-1].id, v2[i].id); return 0; }
时间: 2024-10-15 01:46:00