1 获取网站资源(重点)
2 public void doGet(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException {
3 // 获取网站对象
4 ServletContext context = this.getServletContext();
5 // 获取网站中的静态资源
6 InputStream in = context.getResourceAsStream("/123.bmp");
7 // 获取输出流
8 FileOutputStream out = new FileOutputStream(new File("d:/123.bmp"));
9 // 边读 边写
10 byte[] bs = new byte[1024];
11 int len = 0;
12 while((len = in.read(bs)) != -1){
13 out.write(bs, 0, len);
14 out.flush();
15 }
16 // 释放资源
17 in.close();
18 out.close();
19 }
获取网站资源 getResourceAsStream
时间: 2024-12-08 06:48:19