merge-two-sorted-lists合并链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.

合并两个有序链表

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) {
        ListNode *head=new ListNode(0);
        ListNode *t=head;
        while(l1!=NULL && l2!=NULL)
        {
            if(l1->val<l2->val)
            {
                t->next=l1;
                l1=l1->next;
            }else{
                t->next=l2;
                l2=l2->next;
            }
            t =t->next;
        }
        if(l1!=NULL)
            t->next=l1;
        if(l2!=NULL)
            t->next=l2;
        return head->next;
    }
};

原文地址:https://www.cnblogs.com/zl1991/p/9631781.html

时间: 2024-11-10 16:06:42

merge-two-sorted-lists合并链表的相关文章

leetCode 21. Merge Two Sorted Lists 合并链表

21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目大意:合并两个有序的链表 思路:通过比较两个链表的节点大小,采用尾插法建立链表. 代码如下: /**  * Definition for singly-lin

Leetcode:Merge Two Sorted Lists 合并两个有序单链表

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 代码如下: * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x

[LeetCode] 23. Merge k Sorted Lists 合并k个有序链表

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 与21. Merge Two Sorted Lists的拓展,这道题要合并k个有序链表,还是可以两两合并. 类似题目: [LeetCode] 21. Merge Two Sorted Lists 合并有序链表 原文地址:https://www.cnblogs.com/lightwindy/p/8512

[LeetCode]21 Merge Two Sorted Lists 合并两个有序链表

---恢复内容开始--- [LeetCode]21 Merge Two Sorted Lists 合并两个有序链表 Description Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example Example: Input: 1->2->4, 1-&g

leetCode 21.Merge Two Sorted Lists (合并排序链表) 解题思路和方法

Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思路:对两个已排序的单链表合并.算法上比较简单,与归并排序类似.只是数据结构上以前学的,现在忘的比较多,写第一遍的时候比较费力.而且想把重复代码写出方法,但是方法怎么都不

[Leetcode] Merge k sorted lists 合并k个已排序的链表

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思路:这题最容易想到的是,(假设有k个链表)链表1.2合并,然后其结果12和3合并,以此类推,最后是123--k-1和k合并.至于两链表合并的过程见merge two sorted lists的分析.复杂度的分析见JustDoIT的博客.算法复杂度:假设每个链表的平均长度是n,则1.2合并,遍历2n个

leetCode 23. Merge k Sorted Lists (合并k个排序链表) 解题思路和方法

Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思路:此题是由合并两个排序链表演化而来,刚开始,想法比较简单,像求最大公共前缀一样,逐一求解:但是最后超时,所以马上意识到出题方是为了使用归并和分治的方法,故重新写了代码. 代码一(超时未过): /** * Definition for singly-link

leetcode_21题——Merge Two Sorted Lists(链表)

Merge Two Sorted Lists Total Accepted: 61585 Total Submissions: 188253My Submissions Question Solution Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Hide

[LeetCode]23. Merge k Sorted Lists合并K个排序链表

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [   1->4->5,   1->3->4,   2->6 ] Output: 1->1->2->3->4->4->5->6 要合并K个排好序的链表,我用的方法是用一个优先队列每次存K个元素在队列中,根据优

LeetCode 21. Merge Two Sorted Lists合并两个有序链表 (C++)

题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 分析: 将两个有序链表合并为一个新的有序链表并返