求两个数中二进制位不同的个数

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
int main()
{
 int m = 0, n = 0, x = 0, y = 0;
 int i = 0, count = 0;
 printf("请输入m和n:\n");
 scanf("%d%d", &m, &n);
 for (i = 0; i < 32; i++)
 {
  x = (m >> i) & 1;            //将m的二进制中第i+1位的值赋给x
  y = (n >> i) & 1;             //将n的二进制中第i+1位的值赋给y
  if (x != y)                        //判断x和y是否相等
   count++;
     }
 printf("m和n有%d个位不同\n", count);

system("pause");
 return 0;
}