数码管实验报告

/*************************************************

实验名称：数码管实验一

实验目的：利用动态扫描方法在六位数码管上显示出稳定

的654321

*************************************************/

#include<reg52.h>

#define uchar unsigned char

#define uint unsigned int

sbit DUAN = P2^6;

sbit WEI = P2^7;

uchar code duan_table[]=

{0x3f,0x06,0x5b,0x4f,

0x66,0x6d,0x7d,0x07,

0x7f,0x6f,0x77,0x7c,

0x39,0x5e,0x79,0x71};

uchar code wei_table[]=

{0xfe,0xfd,0xfb,

0xf7,0xef,0xdf};

void delay_1ms(int);

void main()

{

int i,j;

j =0;

while(1)

{

for(i = 7;i > 1; i--)

{

/* P0 = duan_table[i-1];

DUAN = 1;

DUAN = 0;

P0 = 0xff;

P0 = wei_table[j++];

WEI = 1;

WEI = 0;

delay_1ms(1);

以上代码将会产生余晖，改用以下代码消除余晖*/

DUAN = 1;

P0 = duan_table[i-1];

DUAN = 0;

P0 = 0xff;//消除余晖

WEI = 1;

P0 = wei_table[j++];

WEI = 0;

delay_1ms(1);

}

if(j == 6)

j = 0;

}

}

void delay_1ms(int x)

{

int i, j;

for(i = 0; i < x; i++)

for(j = 0; j < 110; j++);

}

/**************************************************

实验名称：数码管实验二

实验目的：利用动态扫描方法和定时器1在数码管的前三位

显示出秒表，精确到1%秒，即后两位显示1%秒，

一直循环下去。（TH/TL填装9216）

**************************************************/

#include<reg52.h>

#define uchar unsigned char

#define uint unsigned int

sbit DUAN = P2^6;

sbit WEI = P2^7;

sbit SPK = P2^3;

uchar S_ms, B_ms, S;

uchar code duan_table0[]=

{0x3f,0x06,0x5b,0x4f,

0x66,0x6d,0x7d,0x07,

0x7f,0x6f,0x77,0x7c,

0x39,0x5e,0x79,0x71};

uchar code duan_table1[]=

{0xbf,0x86,0xdb,0xcf,

0xe6,0xed,0xfd,0x87,

0xff,0xef};

uchar code wei_table[]=

{0xfe,0xfd,0xfb,

0xf7,0xef,0xdf};

void delay_1ms(uchar);

void display(uchar,uchar,uchar);

void main()

{

S_ms = 0;

B_ms = 0;

S = 0;

TMOD = 0x10;

TH1 = (65535-9216)/256;

TL1 = (65535-9216)%256;

EA = 1;

ET1 = 1;

TR1 = 1;

while(1)

{

if(S_ms == 10)

{

S_ms = 0;

B_ms++;

if(B_ms == 10)

{

B_ms = 0;

S++;

SPK = 0;        //每过一秒响一声

delay_1ms(10);  //

SPK = 1;        //

if(S == 10)

{

S=0;

}

}

}

display(S,B_ms,S_ms);

}

}

void delay_1ms(uchar x)

{

uchar i, j;

for(i = 0; i < x; i++)

for(j = 0; j <110; j++);

}

void Time1() interrupt 3

{

TH1 = (65535-9216)/256;

TL1 = (65535-9216)%256;

S_ms++;

}

void display(uchar i,uchar j,uchar k)

{

DUAN = 1;

P0 = duan_table1[i];

DUAN = 0;

P0 = 0xff;

WEI = 1;

P0 = wei_table[0];

WEI = 0;

delay_1ms(1);

DUAN = 1;

P0 = duan_table0[j];

DUAN = 0;

P0 = 0xff;

WEI = 1;

P0 = wei_table[1];

WEI = 0;

delay_1ms(1);

DUAN = 1;

P0 = duan_table0[k];

DUAN = 0;

P0 = 0xff;

WEI = 1;

P0 = wei_table[2];

WEI = 0;

delay_1ms(1);

}

/**************************************************

实验名称：数码管实验三

实验目的：利用动态扫描和定时器1，在数码管上显示出从

765432开始以1%秒的速度往下递减直至764987，

并保持显示次数，与此同时利用定时器0以500ms

的速度进行流水灯从上至下移动，同时蜂鸣器

发声，当数码光上数减到停止时，实验板上流

水灯全部闪烁5次，数码管全熄灭。单片机进入

休眠状态。（0.01秒填装9216）

实验备注：该程序暂时解决不了因中断冲突而引起的数码管

显示延迟

**************************************************/

#include<reg52.h>

#include<intrins.h>

#define uchar unsigned char

#define uint unsigned int

sbit DUAN = P2^6;

sbit WEI = P2^7;

sbit SPK = P2^3;

long num;

uchar swan,wan,qian,bai,shi,ge,flag_0,flag_1;

uchar code duan_table[]=

{0x3f,0x06,0x5b,0x4f,

0x66,0x6d,0x7d,0x07,

0x7f,0x6f,0x77,0x7c,

0x39,0x5e,0x79,0x71};

uchar code wei_table[]=

{0xfe,0xfd,0xfb,

0xf7,0xef,0xdf};

void delay_1ms(uint);

void display(uchar,uchar,uchar,uchar,uchar,uchar);

void main()

{

uchar i;

flag_0 = 0;

flag_1 = 0;

num = 765432;

P1 = 0x7f;

TMOD = 0x11;

TH1 = (65536-9216)/256;

TL1 = (65536-9216)%256;

EA = 1;

ET0 = 1;

ET1 = 1;

// EX0 = 1;

//  EX1 = 1;

TR0 = 1;

TR1 = 1;

while(1)

{

if(flag_0 == 10)

{

flag_0 = 0;

P1 = _cror_(P1,1);

SPK = 0;

delay_1ms(100);

SPK = 1;

}

if(flag_1 == 90)

{

flag_1 = 0;

num = num - 90;

swan = num/100000;

wan = num/10000%10;

qian = num/1000%10;

bai = num/100%10;

shi = num%100/10;

ge = num%10;

}

display(swan,wan,qian,bai,shi,ge);

if(num == 764987)

{

ET0 = 0;

ET1 = 0;

for(i = 0;i < 5;i++)

{

P1 = 0;

SPK = 0;

delay_1ms(500);

P1 = 1;

SPK = 1;

delay_1ms(500);

}

PCON = 0x2;

}

}

}

void delay_1ms(uint x)

{

int i,j;

for(i = 0;i < x;i++)

for(j = 0;j < 110;j++);

}

void display(uchar swan,uchar wan,uchar qian,

uchar bai,uchar shi,uchar ge)

{

DUAN = 1;

P0 = duan_table[swan];

DUAN = 0;

P0 = 0xff;

WEI = 1;

P0 = wei_table[0];

WEI = 0;

delay_1ms(1);

DUAN = 1;

P0 = duan_table[wan];

DUAN = 0;

P0 = 0xff;

WEI = 1;

P0 = wei_table[1];

WEI = 0;

delay_1ms(1);

DUAN = 1;

P0 = duan_table[qian];

DUAN = 0;

P0 = 0xff;

WEI = 1;

P0 = wei_table[2];

WEI = 0;

delay_1ms(1);

DUAN = 1;

P0 = duan_table[bai];

DUAN = 0;

P0 = 0xff;

WEI = 1;

P0 = wei_table[3];

WEI = 0;

delay_1ms(1);

DUAN = 1;

P0 = duan_table[shi];

DUAN = 0;

P0 = 0xff;

WEI = 1;

P0 = wei_table[4];

WEI = 0;

delay_1ms(1);

DUAN = 1;

P0 = duan_table[ge];

DUAN = 0;

P0 = 0xff;

WEI = 1;

P0 = wei_table[5];

WEI = 0;

delay_1ms(1);

}

void Timer0() interrupt 1

{

TH0 = (65536-46080)/256;

TH0 = (65536-46080)%256;

flag_0++;

}

void Timer1() interrupt 3

{

TH1 = (65536-9216)/256;

TL1 = (65536-9216)%256;

flag_1++;

}

//void Ex_int0() interrupt 0

//{}

//void Ex_int1() interrupt 2

//{}