LeetCode_492. Construct the Rectangle

492. Construct the Rectangle

Easy

For a web developer, it is very important to know how to design a web page‘s size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.
2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence.

Example:

Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1].
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Note:

1. The given area won‘t exceed 10,000,000 and is a positive integer
2. The web page‘s width and length you designed must be positive integers.

package leetcode.easy;

public class ConstructTheRectangle {
	private static void print_arr(int[] nums) {
		for (int num : nums) {
			System.out.print(num + " ");
		}
		System.out.println();
	}

	public int[] constructRectangle(int area) {
		int[] arr = new int[2];
		for (int i = (int) Math.sqrt(area); i >= 1; i--) {
			if (area % i == 0) {
				arr[0] = area / i;
				arr[1] = i;
				break;
			}
		}
		return arr;
	}

	@org.junit.Test
	public void test() {
		print_arr(constructRectangle(4));
	}
}

原文地址：https://www.cnblogs.com/denggelin/p/12110473.html