19.1.29 [LeetCode 20] Valid Parentheses

Given a string containing just the characters ‘(‘, ‘)‘, ‘{‘, ‘}‘, ‘[‘ and ‘]‘, determine if the input string is valid.

An input string is valid if:

1. Open brackets must be closed by the same type of brackets.
2. Open brackets must be closed in the correct order.

Note that an empty string is also considered valid.

Example 1:

Input: "()"
Output: true

Example 2:

Input: "()[]{}"
Output: true

Example 3:

Input: "(]"
Output: false

Example 4:

Input: "([)]"
Output: false

Example 5:

Input: "{[]}"
Output: true

 1 class Solution {
 2 public:
 3     bool isValid(string s) {
 4         stack<char>q;
 5         for (int i = 0; s[i]; i++) {
 6             if (s[i] == ‘(‘ || s[i] == ‘[‘ || s[i] == ‘{‘)
 7                 q.push(s[i]);
 8             else if (s[i] == ‘)‘||s[i]==‘]‘||s[i]==‘}‘) {
 9                 if (q.empty())return false;
10                 char c = q.top();
11                 if (s[i] == ‘)‘) {
12                     if (c == ‘(‘)q.pop();
13                     else
14                         return false;
15                 }
16                 else if (s[i] == ‘]‘) {
17                     if (c == ‘[‘)q.pop();
18                     else
19                         return false;
20                 }
21                 else if (s[i] == ‘}‘) {
22                     if (c == ‘{‘)q.pop();
23                     else
24                         return false;
25                 }
26             }
27         }
28         if (!q.empty())return false;
29         return true;
30     }
31 };

原文地址：https://www.cnblogs.com/yalphait/p/10333470.html