【c++程序】继承的几个问题

#include<iostream>
using namespace std;
class Animal
{
private:
	char name[20];
protected:
	int age;
public:
	void setName(char *name)
	{
		strcpy_s(this->name,name);
	}
	void setAge(int age)
	{
		this->age=age;
	}
	char *getName()
	{
		return name;
	}
	int getAge()
	{
		return age;
	}
	void show(bool bNewLine)
	{
		cout<<name<<':'<<age;
		if(bNewLine)
			cout<<endl;
	}
};
class Bird:public Animal
{
	double weight;
public:
	void setWeight(double weight)
	{
		this->weight=weight;
	}
	double getWeight()
	{
		return weight;
	}
	void fly()
	{
		cout<<"我终于翱翔用心凝望"<<endl;
	}
	void visit_parent()
	{
		//cout<<"name="<<name<<endl;//ERROR
		cout<<getName()<<endl;
		cout<<age<<endl;
	}
	void show()
	{
		Animal::show(false);
		cout<<getName()<<'\t'<<getAge()<<'\t'<<weight<<'\t'<<endl;
	}
	void show(bool bNewLine)
	{
		Animal::show(bNewLine);
	}
};
int main()
{
	/*Animal a1,a2;
	a1.setName("团团");
	a1.setAge(300);
	a2.setName("圆圆");
	a2.setAge(200);
	cout<<a1.getName()<<'\t'<<a1.getAge()<<endl;
	cout<<a2.getName()<<'\t'<<a2.getAge()<<endl;*/
	//Animal a1;
	//a1.fly();
	//Animal a1;
	Bird b1;
	b1.setName("鸽子");
	b1.setAge(33);
	b1.setWeight(100);
	//cout<<b1.getName()<<'\t'<<b1.getAge()<<'\t'<<b1.getWeight()<<'\t'<<endl;
	//b1.fly();
	b1.show();//子类的show，会覆盖父类的同名函数
	b1.show(true);//b1.Animal::show(true);
	//cout<<b1.age<<endl;   ERROR
	//cout<<a1.age<<endl;
}