MZL‘s chemistry

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)

Problem Description

MZL define F(X)
as the first ionization energy of the chemical element
X

Now he get two chemical elements U,V,given
as their atomic number,he wants to compare F(U)
and F(V)

It is guaranteed that atomic numbers belongs to the given set:{1,2,3,4,..18,35,36,53,54,85,86}

It is guaranteed the two atomic numbers is either in the same period or in the same group

It is guaranteed that x≠y

Input

There are several test cases

For each test case,there are two numbers u,v,means
the atomic numbers of the two element

Output

For each test case,if F(u)>F(v),print
"FIRST BIGGER",else print"SECOND BIGGER"

Sample Input

1 2
5 3

Sample Output

SECOND BIGGER
FIRST BIGGER

Source

2015 Multi-University Training Contest 5

比较第一电离能的大小，B,Be，O,N,P,S特判一下就好。

#include <iostream>
#include <algorithm>
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <map>
using namespace std;
int main()
{
    int a, b;
    while (scanf("%d%d", &a, &b) != EOF)
    {

        if ((a == 4 && b == 5) || (a == 5 && b == 4))
        {
            if (a>b)
            {
                cout << "SECOND BIGGER" << endl;
            }
            else
                cout << "FIRST BIGGER" << endl;
            continue;
        }
        if ((a == 7 && b == 8) || (a == 8 && b == 7))
        {
            if (a>b)
            {
                cout << "SECOND BIGGER" << endl;
            }
            else
                cout << "FIRST BIGGER" << endl;
            continue;
        }
        if ((a == 15 && b == 16) || (a == 16 && b == 15))
        {
            if (a>b)
            {
                cout << "SECOND BIGGER" << endl;
            }
            else
                cout << "FIRST BIGGER" << endl;
            continue;
        }
        if ((a == 1 && b == 3) || (a == 3 && b == 1))
        {
            if (a>b)
            {
                cout << "SECOND BIGGER" << endl;
            }
            else
                cout << "FIRST BIGGER" << endl;
            continue;
        }
        if ((a == 12 && b == 13) || (a == 13 && b == 12))
        {
            if (a>b)
            {
                cout << "SECOND BIGGER" << endl;
            }
            else
                cout << "FIRST BIGGER" << endl;
            continue;
        }
        if ((a == 1 && b == 3) || (a == 3 && b == 1))
        {
            if (a>b)
            {
                cout << "SECOND BIGGER" << endl;
            }
            else
                cout << "FIRST BIGGER" << endl;
            continue;
        }
        if (a - b>=8 || b - a>=8)
        {
            if (a<b)
                cout << "FIRST BIGGER" << endl;
            else
                cout << "SECOND BIGGER" << endl;
        }
        else
        {
            if (a > b)
                cout << "FIRST BIGGER" << endl;
            else
                cout << "SECOND BIGGER" << endl;
        }
    }
    return 0;
}

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