输入系数a、 b、 c, 求解一元二次方程ax2+bx+c=0的根

#include<iostream>

using namespace std;

#include<cmath>

int main()

{

float a,b,c;

double x1,x2,s;

cout<<"please enter the num：";

cin>>a>>b>>c;

if(b*b-4*a*c>=0)

{

x1=(-b+sqrt(b*b-4*a*c))/(2*a);

x2=(-b-sqrt(b*b-4*a*c))/(2*a);

cout<<"x1="<<x1<<"\n"<<"x2="<<x2<<endl;

}

else

cout<<"方程无实根"<<endl;

return 0;

}