建立一个windows窗体应用程序,在form1界面中拖入两个按钮和一个pictureBox,通过输入输出流来上传图片和显示图片。需要添加一下openFileDialog1.
界面如下:
在cs中写上传和显示图片的方法
1 //上传图片 2 private void button1_Click(object sender, EventArgs e) 3 { 4 //图片的转化 5 openFileDialog1.Filter = "*jpg|*.jpg|*bmp|*.bmp|*gif|*.gif";//设置图片另存为文件类型格式,filter是文件筛选器 6 DialogResult da = openFileDialog1.ShowDialog(); 7 if(da==DialogResult.OK) 8 { 9 string fil = openFileDialog1.FileName; 10 FileStream fs = new FileStream(fil,FileMode.Open,FileAccess.Read); 11 byte[] img=new byte[fs.Length]; 12 BinaryReader br = new BinaryReader(fs);//二进制读取器 13 img = br.ReadBytes(Convert.ToInt32(fs.Length)); 14 //链接数据库 15 SqlConnection conn = new SqlConnection("server=.;database=newData;user=sa;pwd=123"); 16 conn.Open(); 17 SqlCommand cmd = conn.CreateCommand(); 18 cmd.CommandText = "insert into Table_1 values(@image)"; 19 cmd.Parameters.Clear(); 20 cmd.Parameters.Add("@image",img); 21 cmd.ExecuteNonQuery(); 22 conn.Close(); 23 MessageBox.Show("上传成功"); 24 25 }
上传图片的方法
1 //从数据库中读取图片 2 private void button2_Click(object sender, EventArgs e) 3 { 4 SqlConnection conn = new SqlConnection("server=.;database=newData;user=sa;pwd=123"); 5 conn.Open(); 6 SqlCommand cmd = conn.CreateCommand(); 7 cmd.CommandText = "select top 1*from Table_1"; 8 SqlDataReader dr = cmd.ExecuteReader(); 9 dr.Read(); 10 byte[] img = (byte[])dr["Ino"]; 11 // byte[] img1=(byte[])dr["Ino"]; 12 MemoryStream ms = new MemoryStream(img,0,img.Length); 13 ms.Write(img,0,img.Length); 14 Image image = Image.FromStream(ms); 15 this.pictureBox1.SizeMode = PictureBoxSizeMode.Zoom; 16 this.pictureBox1.Image = image; 17 }
从数据库显示图片的方法
时间: 2024-10-09 06:38:55