如何使用C++11令CPU占用率为sin曲线

这题目是老生常谈了，不过多数代码都是针对windows。如今C++11/14让我们可以实现跨平台，使用这份代码几乎可以运行在任何平台。

talking is cheap，show you the code！

 1 #include <iostream>
 2 #include <ratio>
 3 #include <chrono>
 4 #include <thread>
 5 #include <cmath>
 6 int main()
 7 {
 8   using std::chrono::system_clock;
 9   const unsigned int maxCpuSleepMills=100;
10   const double PI=3.1415926;
11   const unsigned int sampleCount=300;
12   const double PI_2=PI*2;
13   int sampleSinMills[sampleCount];
14   for(unsigned int i=0;i<sampleCount;i++)
15   {
16      sampleSinMills[i]=(maxCpuSleepMills/2)+sin(PI_2*i/sampleCount)*(maxCpuSleepMills/2);
17   }
18   while(true){
19     for(unsigned int i=0;i<sampleCount;i++){
20         system_clock::time_point justNow= system_clock::now();
21         std::chrono::duration<int ,std::ratio<1,1000> > sleepMills(sampleSinMills[i]);
22         system_clock::time_point justLater = justNow + sleepMills;
23         while(system_clock::now()<justLater);
24         std::this_thread::sleep_for(std::chrono::milliseconds(maxCpuSleepMills-sampleSinMills[i]));
25     }
26
27   }
28   return 0;
29 }

代码思路一点没有变的。