由0-9表示的数字串,现使其中4个数字不可用,用余下的数字进行重编码。写出编码和解码函数。
前缀编码,前5个剩下的编码用一个数字编码。最后一个以及不可用的4个数字,用两个数字进行编码。
1 class Coding { 2 public: 3 void init(int uncode[], int n) { 4 // get the code left 5 vector<int> left; 6 for (int i = 0, j = 0, m = 0; i < 10; ++i) { 7 if (j < 4 && i == uncode[j]) { 8 j++; 9 continue; 10 } 11 left.push_back(i); 12 if (m < 5) { 13 string code; code += (left[m++] + ‘0‘); 14 codebook[i + ‘0‘] = code; 15 decodebook[code] = i + ‘0‘; 16 } 17 } 18 19 // code for the last one left 20 string code; code; code += (left.back() + ‘0‘); 21 code += (left.front() + ‘0‘); 22 codebook[left.back() + ‘0‘] = code; 23 decodebook[code] = left.back() + ‘0‘; 24 25 //generate codebook for uncode 26 for (int i = 0; i < 4; ++i) { 27 string code; code += (left.back() + ‘0‘); 28 code += (left[i + 1] + ‘0‘); 29 codebook[uncode[i] + ‘0‘] = code; 30 decodebook[code] = (uncode[i] + ‘0‘); 31 } 32 //for (map<char, string>::iterator it = codebook.begin(); it != codebook.end(); it++) 33 // cout << it->first << " " << it->second << endl; 34 } 35 36 string encode(string &str) { 37 if (str.empty()) return ""; 38 stringstream ans; 39 for(int i = 0; i < str.length(); ++i) { 40 ans << codebook[str[i]]; 41 } 42 return ans.str(); 43 } 44 45 string decode(string &str) { 46 if (str.empty()) return ""; 47 stringstream ans; 48 for(int i = 0; i < str.length(); ++i) { 49 string tmp; 50 tmp += str[i]; 51 if (decodebook.find(tmp) != decodebook.end() || 52 (++i < str.length() && decodebook.find(tmp += str[i]) != decodebook.end())){ 53 ans << decodebook[tmp]; 54 } else { 55 return "error"; 56 } 57 } 58 return ans.str(); 59 } 60 private: 61 map<string, char> decodebook; 62 map<char, string> codebook; 63 };
比如uncode={2,5,8,9},编码表就是这样子的:
1 0 0 2 1 1 3 2 71 4 3 3 5 4 4 6 5 73 7 6 6 8 7 70 9 8 74 10 9 76
7用70来编码。
时间: 2024-10-10 12:52:42