uva-----11292 The Dragon of Loowater

Problem C: The Dragon of Loowater


Once upon a time, in the Kingdom of Loowater, a minor nuisance turned
into a major problem.

The shores of Rellau Creek in central Loowater had always been a prime
breeding ground for geese. Due to the lack of predators, the geese population
was out of control. The people of Loowater mostly kept clear of the geese.
Occasionally, a goose would attack one of the people, and perhaps bite off a
finger or two, but in general, the people tolerated the geese as a minor
nuisance.

One day, a freak mutation occurred, and one of the geese spawned a
multi-headed fire-breathing dragon. When the dragon grew up, he threatened to
burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king
was alarmed, and called on his knights to slay the dragon and save the
kingdom.

The knights explained: "To slay the dragon, we must chop off all its heads.
Each knight can chop off one of the dragon‘s heads. The heads of the dragon are
of different sizes. In order to chop off a head, a knight must be at least as
tall as the diameter of the head. The knights‘ union demands that for chopping
off a head, a knight must be paid a wage equal to one gold coin for each
centimetre of the knight‘s height."

Would there be enough knights to defeat the dragon? The king called on his
advisors to help him decide how many and which knights to hire. After having
lost a lot of money building Mir Park, the king wanted to minimize the expense
of slaying the dragon. As one of the advisors, your job was to help the king.
You took it very seriously: if you failed, you and the whole kingdom would be
burnt to a crisp!

Input Specification:


The input contains several test cases. The first line of each test case
contains two integers between 1 and 20000 inclusive, indicating the
number n of heads that the dragon has, and the
number m of knights in the kingdom. The
next n lines each contain an integer, and give the diameters
of the dragon‘s heads, in centimetres. The following m lines
each contain an integer, and specify the heights of the knights of Loowater,
also in centimetres.

The last test case is followed by a line containing:

0 0

Output Specification:

For each test case, output a line containing the minimum number of gold coins
that the king needs to pay to slay the dragon. If it is not possible for the
knights of Loowater to slay the dragon, output the line:

Loowater is doomed!

Sample Input:

2 3
5
4
7
8
4
2 1
5
5
10
0 0

Output for Sample Input:

11
Loowater is doomed!

代码:
题目的大意是 一条大恶龙有很多头,然后你将要派出一些骑士去斩下恶龙的头,每一位骑士只能斩获一个头,但是每派出一个骑士就需要支付一定的货币
,然后问有没有可能斩下所有恶龙的头,若能,最少需要支付多少货币.......!

 1 #include<cstdio>
2 #include<algorithm>
3 using namespace std;
4
5 const int maxn =20000+5;
6 int A[maxn] , B[maxn];
7 int main()
8 {
9 int n,m,i;
10 while(scanf("%d%d",&n,&m)==2&&n&&m)
11 {
12 for(i=0 ; i<n ;i++)
13 scanf("%d",&A[i]);
14 for(i=0 ; i<m ;i++)
15 scanf("%d",&B[i]);
16 sort(A,A+n); //对A进行从小到大排序
17 sort(B,B+m); //对B进行从小到大排序
18 int cur=0;
19 int cost=0;
20 for(i=0;i<m;i++)
21 {
22 if(B[i]>=A[cur])
23 {
24 cost+=B[i];
25 cur ++ ;
26 if(cur == n ) break;
27 }
28 }
29 if(cur<n)
30 printf("Loowater is doomed!\n");
31 else
32 printf("%d\n",cost);
33 }
34 }

时间: 2024-08-26 23:42:24

uva-----11292 The Dragon of Loowater的相关文章

UVa 11292 The Dragon of Loowater 【贪心】

题意:有一条有n个头的恶龙,有m个骑士去砍掉它们的头,每个骑士可以砍直径不超过x的头,问怎样雇佣骑士,使花的钱最少 把头的直径从小到大排序,骑士的能力值也从小到大排序,再一个一个地去砍头 1 #include<iostream> 2 #include<cstdio> 3 #include<cstring> 4 #include <cmath> 5 #include<stack> 6 #include<vector> 7 #includ

UVA 11292 Dragon of Loowater(简单贪心)

Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predato

[2016-03-14][UVA][11292][Dragon of Loowater]

时间:2016-03-14 19:50:12 星期一 题目编号:[2016-03-14][UVA][11292][Dragon of Loowater] 题目大意: 有m个骑士要砍n条龙,每个骑士能看掉龙的头颅当且仅当其实的能力值大于龙的头的直径,每个其实砍掉一条龙需要付出数值上等于能力值的代价,问m个骑士能否砍完所有龙,能则输出最小代价,否则输出"Loowater is doomed!" 输入: 多组数据 每组数据 n m n行 龙头的直径 m行 骑士的能力值 输出: 如果能砍完所有

UVA之11292 Dragon of Loowater

Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predato

UVa 11292 Dragon of Loowater

1 /*UVa 11292 Dragon of Loowater*/ 2 #include<iostream> 3 #include<cstdio> 4 #include<cmath> 5 #include<algorithm> 6 using namespace std; 7 int n,m; 8 int main(){ 9 while(scanf("%d%d",&n,&m) && n!=0 &&

·UVa」 11292 - Dragon of Loowater( 贪心 )

Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predato

UVA它11292 - Dragon of Loowater

Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predato

UVA 题目11292 Dragon of Loowater

Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predato

[UVA] 11292 - Dragon of Loowater [贪心+队列]

Problem C: The Dragon of Loowater Time limit: 1.000 seconds Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese.

1.1-1 Dragon of Loowater, Uva 11292

题目:Dragon of Loowater 问题描述: 思路分析: 把骑士能力从高到低排序,如果能砍掉头就用,代码如下 样例代码: #include<cstdio> #include<algorithm> using namespace std; const int maxn = 20000+5; int A[maxn], B[maxn]; int main() { int n, m; while(scanf("%d%d", &n, &m) ==